Which of the following ions are unlikely to be found in chemical compounds: \(\mathrm{K}^{+}, \mathrm{Ga}^{4+}, \mathrm{Fe}^{6+} \mathrm{S}^{2-}, \mathrm{Ge}^{5+},\) or \(\mathrm{Br}^{-} ?\) Explain briefly.

Short Answer

Expert verified
The ions \(Ga^{4+}\), \(Fe^{6+}\), and \(Ge^{5+}\) are unlikely to be found in chemical compounds as these are not their common oxidation states.

Step by step solution

01

Determine the Common Oxidation States

Evaluate each ion and determine the most common oxidation states. This information can usually be found in a periodic table. For the given ions, K usually forms \(K^{+}\), Ga usually forms \(Ga^{3+}\), Fe usually forms \(Fe^{2+}\) or \(Fe^{3+}\), S usually forms \(S^{2-}\), Ge forms \(Ge^{4+}\), and Br usually forms \(Br^{-}\).
02

Identify Uncommon Oxidation States

Compare the given ions with their common oxidation states. Here, \(Ga^{4+}\), \(Fe^{6+}\), and \(Ge^{5+}\) are not normally found because gallium, iron, and germanium do not usually lose or gain that many electrons to achieve these states. Losing or gaining such amounts of electrons would require a large amount of energy and result in a less stable ion.
03

Conclusion

From the analysis, \(Ga^{4+}\), \(Fe^{6+}\), and \(Ge^{5+}\) are unlikely to be found in chemical compounds due to their uncommon oxidation states.

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Most popular questions from this chapter

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