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Chapter 1: Problem 2

Which of these statements is scientifically correct? "The mass of the student is \(56 \mathrm{~kg}\)." "The weight of the student is \(56 \mathrm{~kg}\)."

Short Answer

Expert verified
The statement 'The mass of the student is 56 kg' is scientifically correct while the statement 'The weight of the student is 56 kg' is not.

Step by step solution

01

Evaluate the statements

First, let's take a look at the two statements one by one. The mass of an object is the amount of matter it contains and is measured in kilograms (kg). Accordingly, saying 'The mass of the student is 56 kg' is scientifically correct.
02

Verify the units

Moving on to the second statement 'The weight of the student is 56 kg', it immediately appears scientifically incorrect. The reason is that weight is the force exerted by the gravity on an object and the unit of force is not kilograms (kg), but newtons (N). Weight is obtained by the product of mass and acceleration due to gravity, which in this case should render a unit of newtons (N), not kilograms (kg).

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Most popular questions from this chapter

A graduated cylinder is filled to the 40.00 -mL mark with a mineral oil. The masses of the cylinder before and after the addition of the mineral oil are \(124.966 \mathrm{~g}\) and \(159.446 \mathrm{~g}\), respectively. In a separate experiment, a metal ball bearing of mass \(18.713 \mathrm{~g}\) is placed in the cylinder and the cylinder is again filled to the 40.00 -mL mark with the mineral oil. The combined mass of the ball bearing and mineral oil is \(50.952 \mathrm{~g}\). Calculate the density and radius of the ball bearing. [The volume of a sphere of radius \(r\) is \(\left.(4 / 3) \pi r^{3} .\right]\)

What is the number of significant figures in each of these measured quantities? (a) \(40.2 \mathrm{~g} / \mathrm{cm}^{3}\), (b) \(0.0000003 \mathrm{~cm}\) (c) \(70 \mathrm{~min}\) (d) \(4.6 \times 10^{19}\) atoms.

The density of ammonia gas under certain conditions is \(0.625 \mathrm{~g} / \mathrm{L} .\) Calculate its density in \(\mathrm{g} / \mathrm{cm}^{3}\).

Percent error is often expressed as the absolute value of the difference between the true value and the experimental value, divided by the true value: Percent error \(=\) \(\frac{\mid \text { true value }-\text { experimental value } \mid}{\mid \text { true value } \mid} \times 100 \%\) where the vertical lines indicate absolute value. Calculate the percent error for these measurements: (a) The density of alcohol (ethanol) is found to be \(0.802 \mathrm{~g} / \mathrm{mL}\). (True value: \(0.798 \mathrm{~g} / \mathrm{mL} .\) ) (b) The mass of gold in an earring is analyzed to be \(0.837 \mathrm{~g}\). (True value: 0.864 g.)

The medicinal thermometer commonly used in homes can be read to \(\pm 0.1^{\circ} \mathrm{F}\), whereas those in the doctor's office may be accurate to \(\pm 0.1^{\circ} \mathrm{C}\). In degrees Celsius, express the percent error expected from each of these thermometers in measuring a person's body temperature of \(38.9^{\circ} \mathrm{C}\).
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