Express the answers to these in scientific notation: (a) \(145.75+\left(2.3 \times 10^{-1}\right)\) (b) \(79,500 \div\left(2.5 \times 10^{2}\right)\) (c) \(\left(7.0 \times 10^{-3}\right)-\left(8.0 \times 10^{-4}\right)\) (d) \(\left(1.0 \times 10^{4}\right) \times\left(9.9 \times 10^{6}\right)\)

Short Answer

Expert verified
(a) \(145.98\), (b) \(3.18 \times 10^{2}\), (c) \(6.2 \times 10^{-3}\), (d) \(9.9 \times 10^{10}\)

Step by step solution

01

Problem (a)

Firstly, \(2.3 \times 10^{-1}\) must be converted to standard form, which equals 0.23. So, the problem becomes \(145.75+0.23\). When adding these numbers, you get \(145.98\).
02

Problem (b)

Firstly, \(2.5 \times 10^{2}\) must be converted to standard form, which equals 250. So, the problem becomes \(79500 \div 250\). Dividing these numbers gives 318. Because this number is larger than 10, it should be expressed in scientific notation, resulting in \(3.18 \times 10^{2}\).
03

Problem (c)

Since these two numbers are already presented in scientific notation, and they have the same order of magnitude, they can be subtracted directly: \(7.0 - 0.8 = 6.2\). After the subtraction, you get \(6.2 \times 10^{-3}\).
04

Problem (d)

When multiplying numbers in scientific notation, we simply need to multiply the decimal parts and add the exponents. In this case, \(1.0 \times 9.9 = 9.9\) and \(10^{4} \times 10^{6} = 10^{10}\). Therefore, the answer is \(9.9 \times 10^{10}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free