Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 1: Problem 40

The density of ammonia gas under certain conditions is \(0.625 \mathrm{~g} / \mathrm{L} .\) Calculate its density in \(\mathrm{g} / \mathrm{cm}^{3}\).

Short Answer

Expert verified
The density of ammonia gas under the given conditions is \(0.000625 \) g/cm^3.

Step by step solution

01

Understand the Conversion

First, you need to understand that the conversion is from larger units (liters) to smaller units (cubic centimeters). Given that 1 liter (L) is equivalent to 1000 cubic centimeters (cm^3), this means when converting to a smaller unit, the value should become smaller.
02

Perform the Conversion

To perform the conversion, utilize the relationship between liters and cubic centimeters. The given density is 0.625g/L. So, divide this value by 1000 (because 1L = 1000 cm^3) to get the density in g/cm^3. Thus, the density in g/cm^3 is \( \frac{0.625}{1000} = 0.000625 \) g/cm^3.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Which of these properties are intensive and which are extensive? (a) length, (b) volume, (c) temperature, (d) mass.

Calculate the mass of each of these: (a) a sphere of gold of radius \(10.0 \mathrm{~cm}\) [the volume of a sphere of radius \(r\) is \(V=\left(\frac{4}{3}\right) \pi r^{3} ;\) the density of gold \(\left.=19.3 \mathrm{~g} / \mathrm{cm}^{3}\right]\) (b) a cube of platinum of edge length \(0.040 \mathrm{~mm}\) (the density of platinum \(\left.=21.4 \mathrm{~g} / \mathrm{cm}^{3}\right),\) (c) \(50.0 \mathrm{~mL}\) of ethanol (the density of ethanol \(=0.798 \mathrm{~g} / \mathrm{mL})\)

In the determination of the density of a rectangular metal bar, a student made the following measurements: length, \(8.53 \mathrm{~cm}\); width, \(2.4 \mathrm{~cm}\); height, \(1.0 \mathrm{~cm}\); mass, 52.7064 g. Calculate the density of the metal to the correct number of significant figures.

Express these numbers in scientific notation: (a) 0.749 ,( b) \(802.6,\) (c) 0.000000621 .

Carry out these operations as if they were calculations of experimental results, and express each answer in the correct units and with the correct number of significant figures: (a) \(7.310 \mathrm{~km} \div 5.70 \mathrm{~km}\) (b) \(\left(3.26 \times 10^{-3} \mathrm{mg}\right)-\left(7.88 \times 10^{-5} \mathrm{mg}\right)\) (c) \(\left(4.02 \times 10^{6} \mathrm{dm}\right)+\left(7.74 \times 10^{7} \mathrm{dm}\right)\) (d) \((7.8 \mathrm{~m}-0.34 \mathrm{~m}) /(1.15 \mathrm{~s}+0.82 \mathrm{~s})\)
See all solutions

Recommended explanations on Chemistry Textbooks

Physical Chemistry

Read Explanation

The Earths Atmosphere

Read Explanation

Making Measurements

Read Explanation

Ionic and Molecular Compounds

Read Explanation

Kinetics

Read Explanation

Chemistry Branches

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free