Aluminum trichloride \(\left(\mathrm{AlCl}_{3}\right)\) is an electron-deficient molecule. It has a tendency to form a dimer (a molecule made of two \(\mathrm{AlCl}_{3}\) units): $$ \mathrm{AlCl}_{3}+\mathrm{AlCl}_{3} \longrightarrow \mathrm{Al}_{2} \mathrm{Cl}_{6} $$ (a) Draw a Lewis structure for the dimer. (b) Describe the hybridization state of \(\mathrm{Al}\) in \(\mathrm{AlCl}_{3}\) and \(\mathrm{Al}_{2} \mathrm{Cl}_{6}\). (c) Sketch the geometry of the dimer. (d) Do these molecules possess a dipole moment?

Short Answer

Expert verified
\(\mathrm{AlCl}_{3}\) is sp2 hybridized and has a trigonal planar structure, while \(\mathrm{Al}_{2} \mathrm{Cl}_{6}\) is sp3 hybridized and has a tetrahedral structure. Both molecules do not have a dipole moment.

Step by step solution

01

Drawing Lewis Structure

A Lewis structure can be drawn for \(\mathrm{Al}_{2} \mathrm{Cl}_{6}\) by linking each \(\mathrm{Al}\) atom to three \(\mathrm{Cl}\) atoms, satisfying the octet rule for the \(\mathrm{Cl}\) atoms. In addition, a lone pair of electrons is also present on one \(\mathrm{Al}\) and another \(\mathrm{Al}\) from another \(\mathrm{AlCl}_{3}\). These lone pairs from two separate \(\mathrm{AlCl}_{3}\) are used to link them together to form the dimer \(\mathrm{Al}_{2} \mathrm{Cl}_{6}\).
02

Describing the Hybridization State

In \(\mathrm{AlCl}_{3}\), each \(\mathrm{Al}\) atom is sp2 hybridized, which means it has a trigonal planar geometry around the \(\mathrm{Al}\) atom. On the other hand, in \(\mathrm{Al}_{2} \mathrm{Cl}_{6}\), \(\mathrm{Al}\) is sp3 hybridized which means it follows a tetrahedral geometry around the \(\mathrm{Al}\) atom.
03

Sketching the Geometry of the Dimer

The geometry of the molecule \(\mathrm{Al}_{2} \mathrm{Cl}_{6}\) is tetrahedral around \(\mathrm{Al}\) atom due to sp3 hybridization. Each \(\mathrm{Al}\) atom is linked to three \(\mathrm{Cl}\) atoms and one \(\mathrm{Al}\) atom.
04

Determining Dipole Moment

In \(\mathrm{Al}_{2} \mathrm{Cl}_{6}\), the \(\mathrm{Cl}\) atoms around each \(\mathrm{Al}\) are perfectly symmetrical. This means there is no net polarity, thus, the molecule does not possess a dipole moment. For \(\mathrm{AlCl}_{3}\), it also does not possess a dipole moment because it has a trigonal planar structure, which makes the polarities to cancel out each other.

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