Draw all possible isomers for the molecule \(\mathrm{C}_{4} \mathrm{H}_{8}\).

Short Answer

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There are three isomers of the molecule \(\mathrm{C}_{4} \mathrm{H}_{8}\). The straight chain configuration, the branched configuration, and the double-bond configuration.

Step by step solution

01

Identifying possible configurations

Identify all possible configurations of the molecule. This molecule has four carbon atoms, so they can be arranged in many ways. The simplest configuration is a straight chain of all four carbons. The carbons can also be arranged in a branch, or include a double bond.
02

Draw the straight-chain configuration

The carbon atoms for the straight chain configuration can be drawn in a straight line. The hydrogen atoms can be filled in to make sure each carbon atom has four bonds. This is the first isomer.
03

Draw the branched configuration

The carbon atoms can also be arranged in a branching configuration. To draw this isomer, rearrange three of the carbon atoms in a straight line and place the fourth carbon in the middle as a branch. Fill in the hydrogen atoms to ensure each carbon atom has four bonds. This is the second isomer.
04

Draw the double-bond configuration

For the last isomer, arrange all four carbon atoms in a straight line and put a double bond between two carbon atoms. Then, add the hydrogen atoms to ensure that each carbon atom (except the two with a double bond who share two) has four bonds. This is the third isomer.

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Most popular questions from this chapter

Fats and oils are names for the same class of compounds, called triglycerides, which contain three ester groups in which \(\mathrm{R}, \mathrm{R}^{\prime},\) and \(\mathrm{R}^{\prime \prime}\) represent long hydrocarbon chains. (a) Suggest a reaction that leads to the formation of a triglyceride molecule, starting with glycerol and carboxylic acids (see p. 398 for structure of glycerol). (b) In the old days, soaps were made by hydrolyzing animal fat with lye (a sodium hydroxide solution). Write an equation for this reaction. (c) The difference between fats and oils is that at room temperature, the former are solid and the latter are liquids. Fats are usually produced by animals, whereas oils are commonly found in plants. The melting points of these substances are determined by the number of \(\mathrm{C}=\mathrm{C}\) bonds (or the extent of unsaturation) present- -the larger the number of \(\mathrm{C}=\mathrm{C}\) bonds, the lower the melting point and the more likely the substance is a liquid. Explain. (d) One way to convert liquid oil to solid fat is to hydrogenate the oil, a process by which some or all of the \(\mathrm{C}=\mathrm{C}\) bonds are converted to \(\mathrm{C}-\mathrm{C}\) bonds. This procedure prolongs shelf life of the oil by removing the more reactive \(\mathrm{C}=\mathrm{C}\) group and facilitates packaging. How would you carry out such a process (that is, what reagents and catalyst would you employ)? (e) The degree of unsaturation of oil can be determined by reacting the oil with iodine, which reacts with the \(\mathrm{C}=\mathrm{C}\) as follows: The procedure is to add a known amount of iodine to the oil and allow the reaction to go to completion. The amount of excess (unreacted) iodine is determined by titrating the remaining iodine with a standard sodium thiosulfate \(\left(\mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}\right)\) solution: $$\mathrm{I}_{2}+2 \mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3} \longrightarrow \mathrm{Na}_{2} \mathrm{~S}_{4} \mathrm{O}_{6}+2 \mathrm{NaI}$$ The number of grams of iodine that reacts with \(100 \mathrm{~g}\) of oil is called the iodine number. In one case, \(43.8 \mathrm{~g}\) of \(\mathrm{I}_{2}\) were treated with \(35.3 \mathrm{~g}\) of corn oil. The excess iodine required \(20.6 \mathrm{~mL}\) of \(0.142 \mathrm{M} \mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}\) for neutralization. Calculate the iodine number of the corn oil.

Use ethane as an example to explain the meaning of conformations. What are Newman projections? How do the conformations of a molecule differ from structural isomers?

Why is it that alkanes and alkynes, unlike alkenes, have no geometric isomers?

A compound having the molecular formula \(\mathrm{C}_{4} \mathrm{H}_{10} \mathrm{O}\) does not react with sodium metal. In the presence of light, the compound reacts with \(\mathrm{Cl}_{2}\) to form three compounds having the formula \(\mathrm{C}_{4} \mathrm{H}_{9} \mathrm{OCl}\). Draw a structure for the original compound that is consistent with this information.

Comment on the extra stability of benzene compared to ethylene. Why does ethylene undergo addition reactions while benzene usually undergoes substitution reactions?

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