Draw all the structural isomers of compounds with the formula \(\mathrm{C}_{4} \mathrm{H}_{8} \mathrm{Cl}_{2}\). Indicate which isomers are chiral and give them systematic names.

Short Answer

Expert verified
The structural isomers of C4H8Cl2 are 1,1-dichlorobutane, 1,2-dichlorobutane, 1,3-dichlorobutane, 2,2-dichlorobutane, 1,2-dichloro-2-methylpropane, and 1,1-dichloro-2-methylpropane, among which only 1,2-dichloro-2-methylpropane is chiral.

Step by step solution

01

Draw all possible isomers of C4H8Cl2

Begin by drawing diagrams for every possible structural isomer of the molecular formula. Four molecules of carbon (C) can form a straight chain or a branched chain. Two chlorine atoms (Cl) can be placed in different positions on these chains, leading to different structural isomers. The possibilities are 1,1-dichlorobutane, 1,2-dichlorobutane, 1,3-dichlorobutane, 2,2-dichlorobutane, 1,2-dichloro-2-methylpropane, and 1,1-dichloro-2-methylpropane.
02

Identify chiral isomers

Look for chiral centers (carbon atoms bonded to four different groups) in the isomers. In this case, only 1,2-dichloro-2-methylpropane has a chiral center. So, it is the only chiral isomer.
03

Assign systematic names to the isomers

The systematic names of the isomers are assigned following IUPAC nomenclature. They are: \[1,1\text{-}dichlorobutane for the first isomer, 1,2\text{-}dichlorobutane for the second isomer, 1,3\text{-}dichlorobutane for the third isomer, 2,2\text{-}dichlorobutane for the fourth isomer, 1,2\text{-}dichloro\text{-}2\text{-}methylpropane for the fifth isomer, and 1,1\text{-}dichloro\text{-}2\text{-}methylpropane for the last isomer.\] Correspondingly, these names describe the structure, positions of functional groups, and the branched chain in the molecule.

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