A face-centered cubic cell contains \(8 \mathrm{X}\) atoms at the corners of the cell and \(6 \mathrm{Y}\) atoms at the faces. What is the empirical formula of the solid?

Short Answer

Expert verified
The empirical formula of the solid is \(XY_{3}\).

Step by step solution

01

Understand the Structure of FCC

In a face-centered cubic (fcc) structure, there are 8 corner atoms and 6 face atoms. In such a structure, each corner atom is shared by eight adjacent cubes and each face atom is shared by two adjacent cubes.
02

Calculate the Contribution of X Atoms

Given that there are 8 corner atoms of type X, and each corner atom is shared by eight adjacent cubes, the contribution of X atoms to one unit cell is \(8*(1/8)\) = 1 atom.
03

Calculate the Contribution of Y Atoms

Given that there are 6 face atoms of type Y, and each face atom is shared by two adjacent cubes, the contribution of Y atoms to one unit cell is \(6*(1/2)\) = 3 atoms.
04

Determine the Empirical Formula

The empirical formula is decided by the ratio of the number of X atoms to the number of Y atoms in the unit cell. Since the unit cell contains 1 X atom and 3 Y atoms, the empirical formula of the solid is \(X_{1}Y_{3}\), or simply \(XY_{3}\).

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