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Chapter 13: Problem 13

Calculate the percent by mass of the solute in each of these aqueous solutions: (a) \(5.50 \mathrm{~g}\) of \(\mathrm{NaBr}\) in \(78.2 \mathrm{~g}\) of solution, (b) \(31.0 \mathrm{~g}\) of \(\mathrm{KCl}\) in \(152 \mathrm{~g}\) of water, \((\mathrm{c})\) \(4.5 \mathrm{~g}\) of toluene in \(29 \mathrm{~g}\) of benzene.

Short Answer

Expert verified
The percent by mass of the solute in each of these aqueous solutions are: (a) 7.03% (b) 20.39% (c) 15.52%

Step by step solution

01

Calculate the percent by mass for Part A

We are given that 5.5 g of NaBr is dissolved in 78.2 g of the solution. Using the formula mentioned earlier, we can calculate the percent by mass = (5.5 g / 78.2 g) x 100 = 7.03%
02

Calculate the percent by mass for Part B

We are to calculate for 31.0 g of KCl in 152 g of water. Again using the formula, percent by mass = (31.0 g / 152 g) x 100 = 20.39%
03

Calculate the percent by mass for Part C

Here we have 4.5 g of toluene in 29 g of benzene. Using the formula, percent by mass = (4.5 g / 29 g) x 100 = 15.52%

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