In each case, indicate which of these pairs of compounds is more likely to form ion pairs in water: (a) \(\mathrm{NaCl}\) or \(\mathrm{Na}_{2} \mathrm{SO}_{4}\) (b) \(\mathrm{MgCl}_{2}\) or \(\mathrm{MgSO}_{4},\) (c) \(\mathrm{LiBr}\) or \(\mathrm{KBr}\)

Short Answer

Expert verified
Among the given pairs, \(\mathrm{Na}_{2} \mathrm{SO}_{4}\), \(\mathrm{MgSO}_{4}\), and \(\mathrm{LiBr}\) are more likely to form ion pairs in water.

Step by step solution

01

Evaluate NaCl and Na2SO4

Sodium Chloride \(\mathrm{NaCl}\) is a strong ionic compound and easily dissolves in water to form ions. However, Sodium Sulphate \(\mathrm{Na}_{2} \mathrm{SO}_{4}\) has two sodium ions and thus, is more likely to form ion pairs due to an increased number of ions dissolving in water.
02

Evaluate MgCl2 and MgSO4

Magnesium Chloride \(\mathrm{MgCl}_{2}\) disassociates into three ions when dissolved in water. Magnesium Sulphate \(\mathrm{MgSO}_{4}\), however, just like Sodium Sulphate from the previous step, also disassociates releasing more ions in the solution. Thus, \(\mathrm{MgSO}_{4}\) is more likely to form ion pairs.
03

Evaluate LiBr and KBr

Both Lithium Bromide \(\mathrm{LiBr}\) and Potassium Bromide \(\mathrm{KBr}\) are strong ionic compounds. However, since the ionization energy of Li is higher than that of K, \(\mathrm{LiBr}\) is more likely to dissociate, forming ions in water. Therefore, \(\mathrm{LiBr}\) will be more likely to form ion pairs in water.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solubility of Ionic Compounds
Understanding the solubility of ionic compounds is essential when predicting their behavior in solutions like water. Solubility refers to the ability of a substance to dissolve in a solvent, creating a homogeneous mixture. In the context of ionic compounds, which are made up of positively and negatively charged ions, their solubility in water depends on the attractive forces between the ions themselves and the water molecules.

Water, being a polar solvent, is very effective at disrupting the ionic lattice of a compound due to its own partial charges. Ions that can become surrounded by water molecules, a process known as hydration, will generally have higher solubility. In our exercise, NaCl and Na2SO4 both dissolve in water, but Na2SO4, having more ions, tends to show a greater degree of ion pairing due to the likelihood of its ions to find each other in solution.
Dissociation of Salts
When we look at the dissociation of salts, such as MgCl2 and MgSO4, we're referring to the process where solid ionic compounds dissolve in water and separate into their constituent ions. The strength of the ionic bond and the structure of the crystal lattice influences how readily a salt dissociates.

Dissociation Processes

For example, MgCl2 splits into one magnesium ion and two chloride ions, resulting in three total ions. Conversely, MgSO4 produces one magnesium ion and one sulfate ion, which still contributes to a higher number of overall particles in solution. This increase can lead to an increased likelihood of forming ion pairs, where the separate ions come back together momentarily in solution, especially at higher concentrations, even though the overall compound remains dissolved.
Ionization Energy
The concept of ionization energy is significant in understanding why certain ions form more readily in water. Ionization energy is the amount of energy required to remove an electron from an atom or ion in its gaseous state. It represents the strength of the electron's attachment to the atom.

As we compare LiBr to KBr, lithium has a higher ionization energy than potassium, which means that lithium holds onto its electrons more tightly and, when forming ions, it does so with more energy release. This energy release helps with the dispersal and hydration of ions in water, making LiBr more predisposed to forming ion pairs in aqueous solution due to its higher tendency to dissociate as compared to KBr.

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Most popular questions from this chapter

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