Can you suggest two reactions that are very slow (take days or longer to complete) and two reactions that are very fast (are over in minutes or seconds)?

Short Answer

Expert verified
Slow reactions: 1) Oxidation of iron (rusting). 2) Reaction between vinegar and eggshell. Fast reactions: 1) Combination of hydrogen and oxygen to form water. 2) Neutralization reaction between sodium hydroxide and hydrochloric acid.

Step by step solution

01

Slow Reactions

Example 1: Oxidation of iron in the presence of water (rusting). The reaction proceeds as follows: 4 Fe(s) + 3 O2(g) -> 2 Fe2O3(s). \ The reaction takes several days and even years depending on the environment, hence it's very slow. \ Example 2: The reaction between vinegar (acetic acid) and eggshell (calcium carbonate) to form calcium acetate, carbon dioxide, and water. This reaction isn’t instantaneous. When an egg is placed into vinegar, you can observe the reaction visually over several days as the eggshell dissolves, leaving the inner membrane intact.
02

Fast Reactions

Example 1: Combination of hydrogen and oxygen to form water. The reaction proceeds as follows: 2H2(g) + O2(g) -> 2H2O(g). \ This reaction is completed within seconds if ignited. \ Example 2: The neutralization reaction between sodium hydroxide (a strong alkali) and hydrochloric acid (a strong acid) to form sodium chloride and water. This reaction is almost instantaneous.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Oxidation of Iron
Oxidation of iron is a common chemical process that you encounter in everyday life. It's the scientific term for what you know as 'rusting'. The reaction can be written as: \[\begin{equation}4\,\text{Fe}(s) + 3\,\text{O}_2(g) \rightarrow 2\,\text{Fe}_2\text{O}_3(s)\end{equation}\]In this chemical equation, iron (Fe) reacts with oxygen (O2) to form iron oxide (Fe2O3), commonly known as rust. This reaction is significantly slow—it can take days, months, or even years to become visually noticeable. Factors such as humidity, temperature, and presence of water or salt can accelerate the process.

Understanding the oxidation of iron is essential in fields like material science and engineering, as it has a direct impact on the durability and lifespan of steel structures and products. Preventing or slowing down oxidation involves methods like coating, painting, or the use of stainless steel, which contains chromium that forms a protective oxide layer over the iron.
Reaction Kinetics
The study of reaction kinetics involves understanding the rates of chemical reactions and the factors influencing them. It explains why certain reactions like the oxidation of iron are sluggish, while others, such as the explosion of hydrogen gas with oxygen, are explosively fast.

Reaction rates can be affected by several factors, such as:
  • Concentration of reactants: Generally, higher concentration results in a faster reaction rate.
  • Temperature: Increasing temperature usually speeds up the reaction as the particles have more energy to collide.
  • Presence of a catalyst: Catalysts lower the activation energy required for the reaction, making it proceed faster.
  • Physical state of reactants: Solids react slower than liquids and gases because of lower molecular mobility and surface area.

Reaction kinetics is fundamental in industries such as pharmaceuticals, where the speed at which a drug reacts affects its efficiency and safety.
Neutralization Reaction
A neutralization reaction is a type of chemical reaction where an acid and a base react to form water and a salt. It can be represented by the general equation:

\[\begin{equation}\text{Acid} + \text{Base} \rightarrow \text{Salt} + \text{H}_2\text{O}\end{equation}\]

One well-known and fast neutralization reaction is the reaction of hydrochloric acid (HCl) with sodium hydroxide (NaOH) to form sodium chloride (NaCl) and water (H2O).

\[\begin{equation}\text{HCl}(aq) + \text{NaOH}(aq) \rightarrow \text{NaCl}(aq) + \text{H}_2\text{O}(l)\end{equation}\]

This reaction occurs almost instantaneously and is exothermic, releasing heat. Neutralization reactions are widely used in various applications including agricultural, medical, and environmental industries to control pH levels. For example, antacids neutralize excess stomach acid to relieve discomfort.
Chemical Equilibrium
Chemical equilibrium occurs in a reversible chemical reaction when the rate of the forward reaction equals the rate of the backward reaction. At this point, the concentrations of reactants and products remain constant over time, although both reactions continue to occur. An example of equilibrium in a chemical system is the synthesis of ammonia (NH3) from nitrogen (N2) and hydrogen (H2).

\[\begin{equation}\text{N}_2(g) + 3\text{H}_2(g) \leftrightharpoons 2\text{NH}_3(g)\end{equation}\]

This dynamic balance does not imply that the reactants and products are in equal concentrations but that their concentrations have stabilized in a fixed ratio. Le Chatelier's Principle describes how a change in conditions (like pressure, temperature, or concentration) can 'shift' the equilibrium position favoring either the forward or reverse reaction. Chemical equilibrium is a vital concept in scientific research and industry, influencing processes like chemical synthesis and the behavior of substances within biological systems.

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Most popular questions from this chapter

The reaction \(2 \mathrm{~A}+3 \mathrm{~B} \longrightarrow \mathrm{C}\) is first order with respect to \(\mathrm{A}\) and \(\mathrm{B}\). When the initial concentrations are \([\mathrm{A}]=1.6 \times 10^{-2} M\) and \([\mathrm{B}]=2.4 \times 10^{-3} M,\) the rate is \(4.1 \times 10^{-4} M / \mathrm{s} .\) Calculate the rate constant of the reaction.

The rate of the reaction $$ \begin{aligned} \mathrm{CH}_{3} \mathrm{COOC}_{2} \mathrm{H}_{5}(a q) &+\mathrm{H}_{2} \mathrm{O}(l) \\ \longrightarrow & \mathrm{CH}_{3} \mathrm{COOH}(a q)+\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}(a q) \end{aligned} $$ shows first-order characteristics-that is, rate \(=\) \(k\left[\mathrm{CH}_{3} \mathrm{COOC}_{2} \mathrm{H}_{5}\right]\) - even though this is a second- order reaction (first order in \(\mathrm{CH}_{3} \mathrm{COOC}_{2} \mathrm{H}_{5}\) and first order in \(\mathrm{H}_{2} \mathrm{O}\) ). Explain.

Use the Arrhenius equation to show why the rate constant of a reaction (a) decreases with increasing activation energy and (b) increases with increasing temperature.

The rate constant for the second-order reaction $$ 2 \mathrm{NOBr}(g) \longrightarrow 2 \mathrm{NO}(g)+\mathrm{Br}_{2}(g) $$ is \(0.80 / M \cdot \mathrm{s}\) at \(10^{\circ} \mathrm{C}\). (a) Starting with a concentration of \(0.086 M,\) calculate the concentration of \(\mathrm{NOBr}\) after \(22 \mathrm{~s}\) (b) Calculate the half-lives when \([\mathrm{NOBr}]_{0}=\) \(0.072 M\) and \([\mathrm{NOBr}]_{0}=0.054 \mathrm{M}\).

The rate constants of some reactions double with every 10 -degree rise in temperature. Assume a reaction takes place at \(295 \mathrm{~K}\) and \(305 \mathrm{~K}\). What must the activation energy be for the rate constant to double as described?

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