Prove the statement that when the concentration of a weak acid HA decreases by a factor of 10 , its percent ionization increases by a factor of \(\sqrt{10}\). State any assumptions.

Short Answer

Expert verified
The original statement is incorrect. When the concentration of a weak acid decreases by a factor of 10, its percent ionization increases by a factor of 10, but not \(\sqrt{10}\).

Step by step solution

01

Understanding Weak Acid Ionization

A weak acid HA ionizes in water to produce H+ and A-. This process can be represented as HA <-> H+ + A-. This dynamic equilibrium is governed by the acid ionization constant, or Ka. The expression for Ka can be written as Ka = \([H^+][A^-] / [HA]\) where \([H^+]\), \([A^-]\) and \([HA]\) represent the molar concentrations of the ions and the weak acid respectively at equilibrium.
02

Representing Percent Ionization

As per the definition, the percent ionization of a weak acid is given by the ratio of the ion concentration to the initial acid concentration, multiplied by 100, expressed as \(( [H^+] / [HA]_0 ) * 100\%\). Since the degree of ionization of a weak acid is small, we can assume that \([HA]\) is approximately equal to the initial concentration \([HA]_0\) at equilibrium. Thus, the percent ionization can also be expressed as \((Ka / [HA]_0 ) * 100\%\).
03

Testing the given Statement

According to the given statement, when the concentration of acid ( [HA] ) decreases by a factor of 10, the percent ionization must increase by a factor of \(\sqrt{10}\). We can test this by substituting [HA] with [HA]/10 in our percent ionization formula, resulting in the formula \((Ka / ([HA]/10) ) * 100\%\), which simplifies to \((Ka*10 / [HA]) * 100\%\). Dividing this by original percent ionization formula, we get the factor as \(\sqrt{100} = 10\) not the \(\sqrt{10}\). Hence, the original statement is incorrect.

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