Chapter 16: Problem 12
Define \(\mathrm{pH}\). Why do chemists normally choose to discuss the acidity of a solution in terms of \(\mathrm{pH}\) rather than hydrogen ion concentration, \(\left[\mathrm{H}^{+}\right] ?\)
Chapter 16: Problem 12
Define \(\mathrm{pH}\). Why do chemists normally choose to discuss the acidity of a solution in terms of \(\mathrm{pH}\) rather than hydrogen ion concentration, \(\left[\mathrm{H}^{+}\right] ?\)
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Get started for freeA solution is made by dissolving \(18.4 \mathrm{~g}\) of \(\mathrm{HCl}\) in 662 \(\mathrm{mL}\) of water. Calculate the \(\mathrm{pH}\) of the solution. (Assume that the volume of the solution is also \(662 \mathrm{~mL} .)\)
Hydrocyanic acid (HCN) is a weak acid and a deadly poisonous compound that, in the gaseous form (hydrogen cyanide), is used in gas chambers. Why is it dangerous to treat sodium cyanide with acids (such as HCl) without proper ventilation?
\(\mathrm{H}_{2} \mathrm{SO}_{4}\) is a strong acid, but \(\mathrm{HSO}_{4}^{-}\) is a weak acid. Account for the difference in strength of these two related species.
List the factors on which the \(K_{\mathrm{a}}\) of a weak acid depends.
What are the concentrations of \(\mathrm{HSO}_{4}^{-}, \mathrm{SO}_{4}^{2-},\) and \(\mathrm{H}^{+}\) in a \(0.20 \mathrm{M} \mathrm{KHSO}_{4}\) solution? (Hint: \(\mathrm{H}_{2} \mathrm{SO}_{4}\) is a strong acid: \(K_{\mathrm{a}}\) for \(\left.\mathrm{HSO}_{4}^{-}=1.3 \times 10^{-2} .\right)\)
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