Identify the acid-base conjugate pairs in each of these reactions: (a) \(\mathrm{CH}_{3} \mathrm{COO}^{-}+\mathrm{HCN} \rightleftharpoons \mathrm{CH}_{3} \mathrm{COOH}+\mathrm{CN}^{-}\) (b) \(\mathrm{HCO}_{3}^{-}+\mathrm{HCO}_{3}^{-} \rightleftharpoons \mathrm{H}_{2} \mathrm{CO}_{3}+\mathrm{CO}_{3}^{2-}\) (c) \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-}+\mathrm{NH}_{3} \rightleftharpoons \mathrm{HPO}_{4}^{2-}+\mathrm{NH}_{4}^{+}\) (d) \(\mathrm{HClO}+\mathrm{CH}_{3} \mathrm{NH}_{2} \rightleftharpoons \mathrm{CH}_{3} \mathrm{NH}_{3}^{+}+\mathrm{ClO}^{-}\) (e) \(\mathrm{CO}_{3}^{2-}+\mathrm{H}_{2} \mathrm{O} \rightleftharpoons \mathrm{HCO}_{3}^{-}+\mathrm{OH}^{-}\) (f) \(\mathrm{CH}_{3} \mathrm{COO}^{-}+\mathrm{H}_{2} \mathrm{O} \rightleftharpoons \mathrm{CH}_{3} \mathrm{COOH}+\mathrm{OH}^{-}\)

Short Answer

Expert verified
The conjugate acid-base pairs are: (a) \(\mathrm{CH}_{3} \mathrm{COO}^{-}\)/\(\mathrm{CH}_{3} \mathrm{COOH}\) and \(\mathrm{HCN}\)/\(\mathrm{CN}^{-}\), (b) \(\mathrm{HCO}_{3}^{-}\)/\(\mathrm{H}_{2} \mathrm{CO}_{3}\) and \(\mathrm{HCO}_{3}^{-}\)/\(\mathrm{CO}_{3}^{2-}\), (c) \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-}\)/\(\mathrm{HPO}_{4}^{2-}\) and \(\mathrm{NH}_{3}\)/\(\mathrm{NH}_{4}^{+}\), (d) \(\mathrm{HClO}\)/\(\mathrm{ClO}^{-}\) and \(\mathrm{CH}_{3} \mathrm{NH}_{2}\)/\(\mathrm{CH}_{3} \mathrm{NH}_{3}^{+}\), (e) \(\mathrm{H}_{2} \mathrm{O}\)/\(\mathrm{OH}^{-}\) and \(\mathrm{CO}_{3}^{2-}\)/\(\mathrm{HCO}_{3}^{-}\), and (f) \(\mathrm{CH}_{3} \mathrm{COO}^{-}\)/\(\mathrm{CH}_{3} \mathrm{COOH}\) and \(\mathrm{H}_{2} \mathrm{O}\)/\(\mathrm{OH}^{-}\).

Step by step solution

01

Identify Conjugate Pairs for Reaction a

For the reaction \( \mathrm{CH}_{3} \mathrm{COO}^{-}+\mathrm{HCN} \rightleftharpoons \mathrm{CH}_{3} \mathrm{COOH}+\mathrm{CN}^{-} \), the acid-base conjugate pairs are \(\mathrm{CH}_{3} \mathrm{COO}^{-}\)/\(\mathrm{CH}_{3} \mathrm{COOH}\) and \(\mathrm{HCN}\)/\(\mathrm{CN}^{-}\). The base \(\mathrm{CH}_{3} \mathrm{COO}^{-}\) becomes the conjugate acid \(\mathrm{CH}_{3} \mathrm{COOH}\) while the acid \(\mathrm{HCN}\) becomes the conjugate base \(\mathrm{CN}^{-}\).
02

Identify Conjugate Pairs for Reaction b

For the reaction \( \mathrm{HCO}_{3}^{-}+\mathrm{HCO}_{3}^{-} \rightleftharpoons \mathrm{H}_{2} \mathrm{CO}_{3}+\mathrm{CO}_{3}^{2-} \), the conjugate pairs are \(\mathrm{HCO}_{3}^{-}\)/\(\mathrm{H}_{2} \mathrm{CO}_{3}\) and another \(\mathrm{HCO}_{3}^{-}\)/\(\mathrm{CO}_{3}^{2-}\).
03

Identify Conjugate Pairs for Reaction c

For the reaction \( \mathrm{H}_{2} \mathrm{PO}_{4}^{-}+\mathrm{NH}_{3} \rightleftharpoons \mathrm{HPO}_{4}^{2-}+\mathrm{NH}_{4}^{+} \), the conjugate pairs are \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-}\)/\(\mathrm{HPO}_{4}^{2-}\) and \(\mathrm{NH}_{3}\)/\(\mathrm{NH}_{4}^{+}\). The base \(\mathrm{NH}_{3}\) becomes the conjugate acid \(\mathrm{NH}_{4}^{+}\) and the acid \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-}\) becomes the conjugate base \(\mathrm{HPO}_{4}^{2-}\).
04

Identify Conjugate Pairs for Reaction d

The reaction \( \mathrm{HClO}+\mathrm{CH}_{3} \mathrm{NH}_{2} \rightleftharpoons \mathrm{CH}_{3} \mathrm{NH}_{3}^{+}+\mathrm{ClO}^{-} \) has the conjugate pairs \(\mathrm{HClO}\)/\(\mathrm{ClO}^{-}\) and \(\mathrm{CH}_{3} \mathrm{NH}_{2}\)/\(\mathrm{CH}_{3} \mathrm{NH}_{3}^{+}\). The base \(\mathrm{CH}_{3} \mathrm{NH}_{2}\) becomes the conjugate acid \(\mathrm{CH}_{3} \mathrm{NH}_{3}^{+}\) and the acid \(\mathrm{HClO}\) becomes the conjugate base \(\mathrm{ClO}^{-}\).
05

Identify Conjugate Pairs for Reaction e

For the reaction \( \mathrm{CO}_{3}^{2-}+\mathrm{H}_{2} \mathrm{O} \rightleftharpoons \mathrm{HCO}_{3}^{-}+\mathrm{OH}^{-} \), the conjugate acid-base pairs are \(\mathrm{H}_{2} \mathrm{O}\)/\(\mathrm{OH}^{-}\) and \(\mathrm{CO}_{3}^{2-}\)/\(\mathrm{HCO}_{3}^{-}\). The base \(\mathrm{CO}_{3}^{2-}\) becomes the conjugate acid \(\mathrm{HCO}_{3}^{-}\) while the acid \(\mathrm{H}_{2} \mathrm{O}\) becomes the conjugate base \(\mathrm{OH}^{-}\).
06

Identify Conjugate Pairs for Reaction f

In the reaction \( \mathrm{CH}_{3} \mathrm{COO}^{-}+\mathrm{H}_{2} \mathrm{O} \rightleftharpoons \mathrm{CH}_{3} \mathrm{COOH}+\mathrm{OH}^{-} \), the pairs are \(\mathrm{CH}_{3} \mathrm{COO}^{-}\)/\(\mathrm{CH}_{3} \mathrm{COOH}\) and \(\mathrm{H}_{2} \mathrm{O}\)/\(\mathrm{OH}^{-}\). The base \(\mathrm{CH}_{3} \mathrm{COO}^{-}\) becomes the conjugate acid \(\mathrm{CH}_{3} \mathrm{COOH}\) and the acid \(\mathrm{H}_{2} \mathrm{O}\) becomes the conjugate base \(\mathrm{OH}^{-}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.

Sign-up for free