Give the conjugate base of each of these acids: (a) \(\mathrm{CH}_{2} \mathrm{ClCOOH},\) (b) \(\mathrm{HIO}_{4}\) (c) \(\mathrm{H}_{3} \mathrm{PO}_{4},\) (d) \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-}\) (e) \(\mathrm{HPO}_{4}^{2-},\) (f) \(\mathrm{H}_{2} \mathrm{SO}_{4},(\mathrm{~g}) \mathrm{HSO}_{4}^{-}\) (h) \(\mathrm{HCOOH}\) (i) \(\mathrm{HSO}_{3}^{-},(\mathrm{j}) \mathrm{NH}_{4}^{+},(\mathrm{k}) \mathrm{H}_{2} \mathrm{~S},\) (l) \(\mathrm{HS}^{-},(\mathrm{m}) \mathrm{HClO}\).

Short Answer

Expert verified
The conjugate bases of the given acids are: (a) \(CH_{2} ClCOO^-\), (b) \(IO_{4}^-\), (c) \(H_{2} PO_{4}^-\), (d) \(HPO_{4}^{2-}\), (e) \(PO_{4}^{3-}\), (f) \(HSO_{4}^{-}\), (g) \(SO_{4}^{2-}\), (h) \(HCOO^-\), (i) \(SO_{3}^{2-}\), (j) \(NH_{3}\), (k) \(HS^-\), (l) \(S^{2-}\), and (m) \(ClO^-\).

Step by step solution

01

- Identify Acids

The compounds provided in the exercise are all acids. They have Hydrogen (H+) ions which they can donate.
02

- Define Conjugate Base

A Conjugate base is formed when an acid loses a proton (H+). Therefore, the conjugate base of the acids mentioned can be found by removing one Hydrogen (H+) ion from them.
03

- Find Conjugate Bases

Now, let us determine the conjugate bases of each acid by removing one H+ ion:(a) \(CH_{2} ClCOO^-\)(b) \(IO_{4}^-\)(c) \(H_{2} PO_{4}^-\)(d) \(HPO_{4}^{2-}\)(e) \(PO_{4}^{3-}\)(f) \(HSO_{4}^{-}\)(g) \(SO_{4}^{2-}\)(h) \(HCOO^-\)(i) \(SO_{3}^{2-}\)(j) \(NH_{3}\)(k) \(HS^-\)(l) \(S^{2-}\)(m) \(ClO^-\)

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