The \(\mathrm{p} K_{\mathrm{b}}\) s for the bases \(\mathrm{X}^{-}, \mathrm{Y}^{-},\) and \(Z^{-}\) are 2.72 \(8.66,\) and \(4.57,\) respectively. Arrange the following acids in order of increasing strength: HX, HY, HZ.

Short Answer

Expert verified
The order of increasing acid strength is HX, HZ, HY.

Step by step solution

01

Understand the relationship between conjugate bases and acids

Acidity and the strength of a base is a conjugate property. If we know one, it can be useful in determining the other. In our case, we know the strengths of the bases (conjugate base of the acids in question) through the given pKb values.
02

Analyze the provided pKb values

The pKb values for the bases X-, Y-, and Z- are 2.72, 8.66, and 4.57, respectively. A lower pKb value indicates a stronger base, because pKb = -log(Kb) and thus a smaller pKb corresponds to a larger Kb. Therefore, in terms of base strength, it follows the order: X- > Z- > Y-.
03

Deduce the order of acid strength

Because the strength of an acid is inversely related to the strength of its conjugate base, the acid formed by the strongest base will be the weakest acid, and vice versa. Therefore, the order of acid strength is the reverse of the base strength order: HY > HZ > HX.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Both \(\mathrm{Ag}^{+}\) and \(\mathrm{Zn}^{2+}\) form complex ions with \(\mathrm{NH}_{3}\). Write balanced equations for the reactions. However, \(\mathrm{Zn}(\mathrm{OH})_{2}\) is soluble in \(6 \mathrm{M} \mathrm{NaOH},\) and \(\mathrm{AgOH}\) is not. Explain.

The ionization constant \(K_{\mathrm{a}}\) of an indicator HIn is \(1.0 \times\) \(10^{-6}\). The color of the nonionized form is red and that of the ionized form is yellow. What is the color of this indicator in a solution whose \(\mathrm{pH}\) is \(4.00 ?\)

A sample of \(0.96 \mathrm{~L}\) of \(\mathrm{HCl}\) at \(372 \mathrm{mmHg}\) and \(22^{\circ} \mathrm{C}\) is bubbled into \(0.034 \mathrm{~L}\) of \(0.57 \mathrm{MH}_{3}\). What is the \(\mathrm{pH}\) of the resulting solution? Assume the volume of solution remains constant and that the \(\mathrm{HCl}\) is totally dissolved in the solution.

For which of these reactions is the equilibrium constant called a solubility product? (a) \(\mathrm{Zn}(\mathrm{OH})_{2}(s)+2 \mathrm{OH}^{-}(a q) \rightleftharpoons \mathrm{Zn}(\mathrm{OH})_{4}^{2-}(a q)\) (b) \(3 \mathrm{Ca}^{2+}(a q)+2 \mathrm{PO}_{4}^{3-}(a q) \rightleftharpoons \mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2}(s)\) (c) \(\mathrm{CaCO}_{3}(s)+2 \mathrm{H}^{+}(a q) \rightleftharpoons\) \(\mathrm{Ca}^{2+}(a q)+\mathrm{H}_{2} \mathrm{O}(l)+\mathrm{CO}_{2}(g)\) (d) \(\mathrm{PbI}_{2}(s) \rightleftharpoons \mathrm{Pb}^{2+}(a q)+2 \mathrm{I}^{-}(a q)\)

Calculate the \(\mathrm{pH}\) of these two buffer solutions: (a) \(2.0 \mathrm{M} \mathrm{CH}_{3} \mathrm{COONa} / 2.0 \mathrm{MCH}_{3} \mathrm{COOH}\), (b) \(0.20 \mathrm{M}\) \(\mathrm{CH}_{3} \mathrm{COONa} / 0.20 \mathrm{M} \mathrm{CH}_{3} \mathrm{COOH}\). Which is the more effective buffer? Why?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free