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Chapter 18: Problem 40

A student placed \(1 \mathrm{~g}\) of each of three compounds \(\mathrm{A}\) \(\mathrm{B},\) and \(\mathrm{C}\) in a container and found that after 1 week no change had occurred. Offer some possible explanations for the fact that no reactions took place. Assume that \(\mathrm{A}, \mathrm{B},\) and \(\mathrm{C}\) are totally miscible liquids.

Short Answer

Expert verified
Possible explanations for no reaction taking place might be the high chemical stability of the compounds A, B, and C, non-conducive conditions for reactions within the container such as temperature or pressure, absence of a necessary catalyst or inadequate concentration of the compounds.

Step by step solution

01

Understand the Concept of a Chemical Reaction

A chemical reaction occurs when substance A reacts with substance B to form a new substance C, or when a single compound breaks down into two or more substances. For a reaction to occur, the reactants must come into direct chemical contact with each other. The rate at which a reaction proceeds can be influenced by several factors such as the presence of a catalyst, concentration of reactants, temperature, and pressure.
02

Analyze Given Compounds A, B and C

Given the fact that no reaction occurred, it can be hypothesized that either the conditions necessitating a reaction were missing, or that the three compounds are inert or stable and do not easily undergo reactions.
03

Possible Reasons for No Reaction

One possible reason that no reaction occurred could be that all compounds A, B and C are chemically stable and do not easily react with other substances. Another possible explanation is that the conditions in the container (e.g., temperature, pressure) were not conducive to facilitating a reaction between the compounds. It is also possible that a catalyst was required to trigger the reaction, but it was missing. The concentration of the compounds could also have been too low to initiate a reaction.

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Most popular questions from this chapter

The molar heat of vaporization of ethanol is \(39.3 \mathrm{~kJ} / \mathrm{mol}\) and the boiling point of ethanol is \(78.3^{\circ} \mathrm{C}\) Calculate \(\Delta S\) for the vaporization of \(0.50 \mathrm{~mol}\) ethanol.

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