A galvanic cell using \(\mathrm{Mg} / \mathrm{Mg}^{2+}\) and \(\mathrm{Cu} / \mathrm{Cu}^{2+}\) half-cell's operates under standard-state conditions at \(25^{\circ} \mathrm{C}\) and each compartment has a volume of \(218 \mathrm{~mL}\). The cell delivers 0.22 A for \(31.6 \mathrm{~h}\). (a) How many grams of \(\mathrm{Cu}\) are deposited? (b) What is the \(\left[\mathrm{Cu}^{2+}\right]\) remaining?

Short Answer

Expert verified
The mass of Copper deposited is obtained after converting the charge into moles and the moles into grams. The remaining concentration of Copper ions is calculated after using the stoichiometry of the reaction to find the moles of Copper ions used and subtracting it from the initial moles.

Step by step solution

01

Calculate total charge passed

Firstly, the total charge passed through the cell needs to be calculated. Current (I) is the rate of flow of charge. It is given by the formula I = Q/t where Q is the total charge and t is the time. You are given I = 0.22A and t = 31.6 hours which must be converted into seconds. Multiply the time by 60 twice to convert hours to minutes and then minutes to seconds. Afterward, rearrange the formula to find Q = I*t.
02

(a) Calculate grams of Copper deposited

Faraday's laws of electrolysis state that the amount of substance produced at an electrode during electrolysis is directly proportional to the amount of charge passed through the cell. Therefore, the moles of Copper deposited can be calculated by the formula Q = n*F, where n is the number of moles, F is Faraday's constant (\(96485 C/mol\)). Rearrange to find n = Q/F. Then, convert moles to grams knowing that the molar mass of Copper is \(63.55 g/mol\).
03

(b) Calculate the remaining concentration of Copper ions

The galvanic cell proceeding in the question is: \(Mg + Cu^{2+} -> Mg^{2+} + Cu\), which shows that for each mole of Copper deposited, one mole of Copper ions was used up. Therefore, the moles of Copper ions used is equal to the moles of Copper deposited. Calculate the initial concentration of Copper ions using the molarity (M) formula: M = n/V, knowing that V = 218 mL = 0.218 L and assuming that initially, the solution was 1 M. Subtract the moles of Copper ions used from the initial moles. Lastly, calculate the remaining concentration of Copper ions using the new moles and the volume.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Faraday's Laws of Electrolysis
Faraday's laws of electrolysis are critical to understanding how electroplating and batteries work. The first law states that the mass of a substance altered at an electrode during electrolysis is proportional to the quantity of electric charge passed through the circuit. This is quantitatively expressed as \( m = (Q/F) \times M \), where \( m \) is the mass of substance altered, \( Q \) is the total electric charge, \( F \) is Faraday's constant (approximately 96485 C/mol), and \( M \) is the molar mass of the substance.

This means, if you know the current and the duration of electrolysis, you can calculate how much substance is deposited on an electrode. In the context of a galvanic cell, where a current is produced because of a spontaneous electrochemical reaction, Faraday's laws help us determine the quantity of metal deposited from the electrolyte onto an electrode over time. Inspecting this fundamental principle guides students to accurately predict and calculate the outcomes of electrochemical processes.
Electrochemical Reaction
An electrochemical reaction involves the movement of electrons from one substance to another. In a galvanic, or voltaic, cell, this process happens spontaneously and results in the generation of electrical energy. The cell consists of two half-cells: one where oxidation occurs (loss of electrons) and another where reduction happens (gain of electrons). These half-cells are connected by a salt bridge that maintains electrical neutrality.

The overall reaction in a galvanic cell can be understood through the individual reactions at the anode and cathode. For instance, in the case of a \( Mg/Cu^{2+} \) cell, \( Mg \) is oxidized to \( Mg^{2+} \) at the anode, while \( Cu^{2+} \) ions are reduced to solid \( Cu \) at the cathode. Since these reactions involve the transfer of electrons, they can be quantified via the flow of current. As current passes through the cell, it quantifies electron flow which, in turn, indicates how much of a material has undergone electrochemical change.
Molarity Calculation
Molarity (or molar concentration) is a measurement of the concentration of a solute in a solution. It is defined as the number of moles of solute per liter of solution, and its unit is moles per liter (mol/L). The formula for molarity is given by \( M = n/V \), where \( n \) is the number of moles of the solute, and \( V \) is the volume of the solution in liters.

This concentration calculation is crucial in chemistry as it allows us to predict how substances will react with one another in a solution. When dealing with a galvanic cell, after an electrochemical reaction has progressed, the molarity of the electrolyte will change as ions are deposited as solids on the electrodes. This is precisely why after copper is deposited on the cathode, the concentration of \( Cu^{2+} \) ions in the solution decreases. To determine the remaining concentration, we subtract the moles of \( Cu^{2+} \) consumed in the reaction from the initial moles present in the solution, then we use the molarity formula with the new number of moles and the same volume to find the final concentration.

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Most popular questions from this chapter

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