Which species in each pair is a better oxidizing agent under standard-state conditions? (a) \(\mathrm{Br}_{2}\) or \(\mathrm{Au}^{3+},\) (b) \(\mathrm{H}_{2}\) or \(\mathrm{Ag}^{+}\) (c) \(\mathrm{Cd}^{2+}\) or \(\mathrm{Cr}^{3+},\) (d) \(\mathrm{O}_{2}\) in acidic media or \(\mathrm{O}_{2}\) in basic media.

Short Answer

Expert verified
The species with the more positive reduction potential in each pair is the better oxidizing agent. The exact answers would depend on the values obtained from a standard reduction potentials table. However, as a general rule of thumb, elements in their elemental state, such as \( \mathrm{Br}_{2}\) and \( \mathrm{H}_{2}\), have a reduction potential of zero. Thus, unless the other species in the pair has a negative standard reduction potential, they are usually the weaker oxidizing agents. Additionally, \( \mathrm{O}_{2}\) in acidic media is generally a stronger oxidizing agent compared to \( \mathrm{O}_{2}\) in basic media.

Step by step solution

01

- Identify Reduction Potentials

Use a standard reduction potentials table to find the reduction potential for each species in the pairs. Using this data, the better oxidizing agent can be determined because the one with the greater standard reduction potential is a better oxidizing agent.
02

- Compare Reduction Potentials

Compare the reduction potentials of \( \mathrm{Br}_{2}\) and \( \mathrm{Au}^{3+}\). The species with the more positive reduction potential is the better oxidizing agent. Do the same comparison for each pair.
03

- Identify Oxidizing Agents

Repeat step 2 for the remaining pairs \( \mathrm{H}_{2}\) and \( \mathrm{Ag}^{+}\), \( \mathrm{Cd}^{2+}\) and \( \mathrm{Cr}^{3+}\), and \( \mathrm{O}_{2}\) in acidic media and \( \mathrm{O}_{2}\) in basic media. This will complete the evaluation of the better oxidizing agent for each pair.

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