Consider a galvanic cell composed of the SHE and a half-cell using the reaction \(\mathrm{Ag}^{+}(a q)+e^{-} \rightarrow \operatorname{Ag}(s)\). (a) Calculate the standard cell potential. (b) What is the spontaneous cell reaction under standard-state conditions? (c) Calculate the cell potential when \(\left[\mathrm{H}^{+}\right]\) in the hydrogen electrode is changed to (i) \(1.0 \times\) \(10^{-2} M\) and (ii) \(1.0 \times 10^{-5} M,\) all other reagents being held at standard-state conditions. (d) Based on this cell arrangement, suggest a design for a pH meter.

Short Answer

Expert verified
The standard cell potential is +0.80V. The spontaneous reaction is the reduction of silver ions to metallic silver and the oxidation of hydrogen. The cell potentials, when the concentration of [H+] changes, are 0.82V and 0.90V. The design of a pH meter can be based on this cell arrangement, using the cell potential to calculate the hydrogen ion concentration, and thus determine the pH.

Step by step solution

01

Calculation of Standard Cell Potential

For the given half-cell reaction, the standard reduction potential, \(E^0_{Ag+/Ag}\) is given as +0.80 V. The other half-cell is the standard hydrogen electrode (SHE) i.e., \(2H+ + 2e- → H2\) having a standard reduction potential, \(E^0_{H+/H2}\)= 0 V. The galvanic cell reaction can be given as: \(Ag+ + H2 → Ag + 2H+\) with the standard cell potential as \(E^0_{cell} = E^0_{cathode} - E^0_{anode}\). Here, Ag+/Ag is the cathode and H+/H2 is the anode. So, \(E^0_{cell} = E^0_{Ag+/Ag} - E^0_{H+/H2} = +0.80V - 0 = +0.80V.\)
02

Determining the Spontaneous Cell Reaction

When the standard cell potential is positive, the reaction is spontaneous. So, the cell reaction will proceed in the direction of the reduction of silver ions to metallic silver and the oxidation of hydrogen.
03

Calculation of Cell Potential with Changed Concentration

We use the Nernst equation to calculate the effect of changing concentration on the cell potential. Nernst equation is given as \(E_{cell} = E_{cell}^0 - \frac{0.0591}{n}logQ\), where n is the number of electrons exchanged in the reaction and Q is the reaction quotient. (i) When [H+] = 1.0 x 10^-2 M, the nernst equation becomes: \(E_{cell}= E_{cell}^0 - \frac{0.0591}{2}log {\frac{1.0 × 10^-2}{1}} =0.80V - 0.015 log10^-2 = 0.82V\). Similarly, by substituting [H+] =1.0 x 10^-5 M in the Nernst equation, we get: \(E_{cell}= E_{cell}^0 - \frac{0.0591}{2}log {\frac{1.0 × 10^-5}{1}} =0.80V - 0.015 log10^-5 = 0.90V\).
04

Design of a pH meter

A typical pH meter can be designed based on this galvanic cell arrangement. The voltmeter measures the potential difference which is used for calculating hydrogen ion concentration. This cell potential is a function of pH (as pH = - log[H+]), so the pH of the solution is directly identified from the cell potential. A correction factor is obtained from buffer solutions of known pH to increase measurement accuracy. Hence, this cell arrangement can be used to design a pH meter.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Cell Potential
Understanding the standard cell potential is central to studying galvanic or voltaic cells, a class of electrochemical cells that generate electrical energy through spontaneous redox reactions. The standard cell potential, denoted as \(E^0_{cell}\), is a measure of the electromotive force of a cell when all species are in their standard states, typically at a concentration of 1 M and pressure of 1 atmosphere, at a temperature of 25°C (298 K).

To calculate \(E^0_{cell}\), we take the difference between the standard reduction potentials of the cathode (reduction half-cell) and the anode (oxidation half-cell). For instance, in a cell composed of a silver half-cell and a standard hydrogen electrode (SHE), the standard cell potential is found using the formula \(E^0_{cell} = E^0_{cathode} - E^0_{anode}\). With \(E^0_{Ag+/Ag}\) at +0.80V (silver half-cell) and \(E^0_{H+/H2}\) at 0V (SHE), we get a standard cell potential of +0.80V. This positive value indicates that the cell can perform work when the reaction proceeds spontaneously under standard conditions.
Spontaneous Cell Reaction
A spontaneous cell reaction is one that occurs without an external energy input; the cell can do electrical work on its surroundings as the reaction unfolds. The spontaneity of the reaction in a galvanic cell is indicated by the sign of the standard cell potential (\(E^0_{cell}\)).

When the standard cell potential is positive, as in our exercise's example of +0.80V, this signifies a tendency for the cell reaction to occur on its own. Essentially, this means that the reduction of silver ions to solid silver and the oxidation of molecular hydrogen to hydrogen ions are processes that release energy. Ultimately, identifying a positive standard cell potential is key in predicting that the reaction will proceed without external interference, providing necessary insight for the design and operation of electrochemical cells and devices.
Nernst Equation
The Nernst equation is a fundamental tool in electrochemistry, allowing us to compute the actual cell potential under non-standard conditions, which includes variations in temperature, pressure, or concentration of reactants and products. The equation is given by:

\(E_{cell} = E_{cell}^0 - \frac{0.0591}{n} \log Q\),

where \(E_{cell}^0\) is the standard cell potential, \(n\) is the number of moles of electrons transferred in the reaction, and \(Q\) is the reaction quotient. The reaction quotient reflects the ratio of the concentrations of products and reactants at any given point during the reaction, not to be confused with the equilibrium constant \(K\), which is the value of \(Q\) when the reaction is at equilibrium.

The application of the Nernst equation shows that as the concentrations of reactants or products change, the cell potential also changes. This is calculated using the logarithm of the reaction quotient, which means that even small changes in concentration can have a significant effect on the potential. This variable dependency allows chemists to manipulate and control the energetic output of electrochemical reactions.
pH Meter Design
The principles of electrochemistry are adeptly applied in designing pH meters, which are instruments used to measure the acidity or basicity of a solution. In our exercise, we saw that the potential of a galvanic cell changes with the hydrogen ion concentration in the hydrogen electrode, a concept utilized in pH meter technology.

A pH meter often consists of a voltmeter connected to a pair of electrodes immersed in the tested solution. One electrode is sensitive to the hydrogen ion concentration, acting similarly to the hydrogen electrode in our galvanic cell example. As the cell's potential varies with the hydrogen ion concentration, which is inversely related to pH (since \(pH = - \log [ H^+ ]\)), the voltmeter readings can directly correlate to the pH value of the solution.

To ensure precision, the pH meter is usually calibrated using standard buffer solutions with known pH values. This calibration allows for the correction of systematic errors, leading to more accurate and reliable measurements. Thus, a well-designed pH meter is capable of providing immediate, accurate assessments of solution acidity, which is indispensable in numerous scientific, industrial, and environmental applications.

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Most popular questions from this chapter

A galvanic cell is constructed by immersing a piece of copper wire in \(25.0 \mathrm{~mL}\) of a \(0.20 \mathrm{M} \mathrm{CuSO}_{4}\) solution and a zinc strip in \(25.0 \mathrm{~mL}\) of a \(0.20 \mathrm{M} \mathrm{ZnSO}_{4}\) solution. (a) Calculate the emf of the cell at \(25^{\circ} \mathrm{C}\) and predict what would happen if a small amount of concentrated \(\mathrm{NH}_{3}\) solution were added to (i) the \(\mathrm{CuSO}_{4}\) solution and (ii) the \(\mathrm{ZnSO}_{4}\) solution. Assume that the volume in each compartment remains constant at \(25.0 \mathrm{~mL}\). (b) In a separate experiment, \(25.0 \mathrm{~mL}\) of \(3.00 M \mathrm{NH}_{3}\) are added to the \(\mathrm{CuSO}_{4}\) solution. If the emf of the cell is \(0.68 \mathrm{~V},\) calculate the formation constant \(\left(K_{\mathrm{f}}\right)\) of \(\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}^{2+}\).

"Galvanized iron" is steel sheet that has been coated with zinc; "tin" cans are made of steel sheet coated with tin. Discuss the functions of these coatings and the electrochemistry of the corrosion reactions that occur if an electrolyte contacts the scratched surface of a galvanized iron sheet or a tin can.

Explain why most useful galvanic cells give voltages of no more than 1.5 to \(2.5 \mathrm{~V}\). What are the prospects for developing practical galvanic cells with voltages of \(5 \mathrm{~V}\) or more?

The oxidation of \(25.0 \mathrm{~mL}\) of a solution containing \(\mathrm{Fe}^{2+}\) requires \(26.0 \mathrm{~mL}\) of \(0.0250 \mathrm{M} \mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\) in acidic solution. Balance the following equation and calculate the molar concentration of \(\mathrm{Fe}^{2+}\): $$ \mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}+\mathrm{Fe}^{2+}+\mathrm{H}^{+} \longrightarrow \mathrm{Cr}^{3+}+\mathrm{Fe}^{3+} $$

Oxalic acid \(\left(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\right)\) is present in many plants and vegetables. (a) Balance the following equation in acid solution: $$ \mathrm{MnO}_{4}^{-}+\mathrm{C}_{2} \mathrm{O}_{4}^{2-} \longrightarrow \mathrm{Mn}^{2+}+\mathrm{CO}_{2} $$ (b) If a 1.00 -g sample of \(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\) requires \(24.0 \mathrm{~mL}\) of \(0.0100 M \mathrm{KMnO}_{4}\) solution to reach the equivalence point, what is the percent by mass of \(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\) in the sample?

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