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Chapter 2: Problem 45

Which of the following compounds are likely to be ionic? Which are likely to be molecular? \(\mathrm{SiCl}_{4}\), LiF, \(\mathrm{BaCl}_{2}, \mathrm{~B}_{2} \mathrm{H}_{6}, \mathrm{KCl}, \mathrm{C}_{2} \mathrm{H}_{4}\)

Short Answer

Expert verified
\(\mathrm{SiCl}_{4}, \mathrm{B}_{2}\mathrm{H}_{6}, \mathrm{C}_{2} \mathrm{H}_{4}\) are molecular whereas \(\mathrm{LiF}\), \(\mathrm{BaCl}_{2}\), \(\mathrm{KCl}\) are ionic.

Step by step solution

01

Identify The Type of Elements in Each Compound

For each compound, identify the types of elements present. In \(\mathrm{SiCl}_{4}\), Si (Silicon) is a metalloid, and Cl (Chlorine) is a non-metal. In \(\mathrm{LiF}\), Li (Lithium) is a metal, and F (Fluorine) is a non-metal. In BaCl2, Ba (Barium) is a metal and Cl is non-metal. In B2H6, B (Boron) is a metalloid and H (Hydrogen) is a non-metal. In KCl, K (Potassium) is a metal, and Cl is a non-metal. In C2H4, C (Carbon) is a non-metal, and H is a non-metal.
02

Determine the type of Bonding in the Compounds

Next, let's determine the type of bonding in the compounds. Compounds formed from metals and non-metals are ionic and those formed from non-metals are molecular. Thus, LiF, BaCl2, and KCl are ionic compounds as they're made from metal and non-metal. SiCl4, B2H6, and C2H4 are molecular compounds, as they're made from non-metals only.

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