Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 2: Problem 48

Name these compounds: (a) \(\mathrm{KClO},\) (b) \(\mathrm{Ag}_{2} \mathrm{CO}_{3}\), (c) \(\mathrm{FeCl}_{2},\) (d) \(\mathrm{KMnO}_{4},\) (e) \(\mathrm{CsClO}_{3},\) (f) \(\mathrm{HIO}\) (g) \(\mathrm{FeO}\) (h) \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) (i) \(\mathrm{TiCl}_{4},\) (j) \(\mathrm{NaH},(\mathrm{k}) \mathrm{Li}_{3} \mathrm{~N},\) (l) \(\mathrm{Na}_{2} \mathrm{O}\) \((\mathrm{m}) \mathrm{Na}_{2} \mathrm{O}_{2},(\mathrm{n}) \mathrm{FeCl}_{3} \cdot 6 \mathrm{H}_{2} \mathrm{O}\)

Short Answer

Expert verified
The names of the compounds are: (a) Potassium Hypochlorite, (b) Silver Carbonate, (c) Iron(II) Chloride, (d) Potassium Permanganate, (e) Cesium Chlorate, (f) Hydroiodic Acid, (g) Iron(II) Oxide, (h) Iron(III) Oxide, (i) Titanium(IV) Chloride, (j) Sodium Hydride, (k) Lithium Nitride, (l) Sodium Oxide, (m) Sodium Peroxide, and (n) Iron(III) Chloride Hexahydrate.

Step by step solution

01

Naming Potassium Hypochlorite

For \(\mathrm{KClO}\), \(\mathrm{K}\) stands for Potassium, an alkali metal that only has one possible charge, \(+1\). \(\mathrm{ClO}\) is a polyatomic ion called hypochlorite. Thus the compound is called Potassium Hypochlorite.
02

Naming Silver Carbonate

In \(\mathrm{Ag}_{2}\mathrm{CO}_{3}\), \(\mathrm{Ag}\) represents Silver, which only has one oxidation state, \(+1\). \(\mathrm{CO}_{3}\) is a polyatomic ion known as carbonate. Thus the name is Silver Carbonate.
03

Naming Iron(II) Chloride

For \(\mathrm{FeCl}_{2}\), \(\mathrm{Fe}\) is Iron, a transition metal that can have multiple charges. \(\mathrm{Cl}\) is Chlorine ion. Since there are 2 Chlorine atoms each with a \( -1 \) charge, the charge on Iron must be \( +2 \). The compound is called Iron(II) Chloride.
04

Naming Potassium Permanganate

In \(\mathrm{KMnO}_{4}\), \(\mathrm{K}\) is Potassium and \(\mathrm{MnO}_{4}\) is a polyatomic ion known as permanganate. Therefore, the name is Potassium Permanganate.
05

Naming Cesium Chlorate

For \(\mathrm{CsClO}_{3}\), \(\mathrm{Cs}\) represents Cesium, and \(\mathrm{ClO}_{3}\) is a polyatomic ion called chlorate. Hence, the compound's name is Cesium Chlorate.
06

Naming Hydroiodic Acid

For \(\mathrm{HIO}\), \(\mathrm{H}\) is Hydrogen, and \(\mathrm{IO}\) is iodate ion. As the compound is between Hydrogen and a polyatomic ion and it is aqueous, we name it as an acid. Hence the name is Hydroiodic Acid.
07

Naming Iron(II) Oxide

For \(\mathrm{FeO}\), since there's 1 Oxide ion carrying \(-2\) charge, the Iron ion must have a \(+2\) charge. Therefore, the name of the compound is Iron(II) Oxide.
08

Naming Iron(III) Oxide

In \(\mathrm{Fe}_{2} \mathrm{O}_{3}\), each Iron atom carries a \(+3\) charge to balance the 3 Oxide ions each carrying a \(-2\) charge. Hence, the compound is called Iron(III) Oxide.
09

Naming Titanium(IV) Chloride

In \(\mathrm{TiCl}_{4}\), each Chlorine atom carries a \(-1\) charge. To balance the 4 Chlorine atoms, the Titanium atom must have a \(+4\) charge. The compound is therefore called Titanium(IV) Chloride.
10

Naming Sodium Hydride

For \(\mathrm{NaH}\), \(\mathrm{Na}\) is Sodium and \(\mathrm{H}\) is Hydride (the name given to Hydrogen when it carries a negative charge). Thus, the compound's name is Sodium Hydride.
11

Naming Lithium Nitride

For \(\mathrm{Li}_{3}\mathrm{N}\), \(\mathrm{Li}\) is Lithium and \(\mathrm{N}\) is Nitride (which is the name given to Nitrogen when it carries a negative charge). Hence, the compound is Lithium Nitride.
12

Naming Sodium Oxide

For \(\mathrm{Na}_{2} \mathrm{O}\), \(\mathrm{Na}\) is Sodium and \(\mathrm{O}\) is Oxide. Thus, the name of the compound is Sodium Oxide.
13

Naming Sodium Peroxide

For \(\mathrm{Na}_{2} \mathrm{O}_{2}\), \(\mathrm{Na}\) is Sodium and \(\mathrm{O}_{2}\) is a polyatomic ion known as peroxide. Therefore, the compound is called Sodium Peroxide.
14

Naming Iron(III) Chloride Hexahydrate

For \(\mathrm{FeCl}_{3}\cdot 6 \mathrm{H}_{2} \mathrm{O}\), we have Iron(III) Chloride from before, and the \(\cdot 6 \mathrm{H}_{2} \mathrm{O}\) indicates that there are 6 water molecules for each unit of Iron(III) Chloride, known as a hydrate. Hence, the name is Iron(III) Chloride Hexahydrate.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

On p. 30 it was pointed out that mass and energy are alternate aspects of a single entity called massenergy. The relationship between these two physical quantities is Einstein's famous equation, \(E=m c^{2}\), where \(E\) is energy, \(m\) is mass, and \(c\) is the speed of light. In a combustion experiment, it was found that \(12.096 \mathrm{~g}\) of hydrogen molecules combined with \(96.000 \mathrm{~g}\) of oxygen molecules to form water and re- leased \(1.715 \times 10^{3} \mathrm{~kJ}\) of heat. Calculate the corresponding mass change in this process and comment on whether the law of conservation of mass holds for ordinary chemical processes. (Hint: The Einstein equation can be used to calculate the change in mass as a result of the change in energy. \(1 \mathrm{~J}=1 \mathrm{~kg} \mathrm{~m}^{2} / \mathrm{s}^{2}\) and \(\left.c=3.00 \times 10^{8} \mathrm{~m} / \mathrm{s} .\right)\)

A common mineral of barium is barytes, or barium sulfate \(\left(\mathrm{BaSO}_{4}\right)\). Because elements in the same periodic group have similar chemical properties, we might expect to find some radium sulfate \(\left(\mathrm{RaSO}_{4}\right)\) mixed with barytes because radium is the last member of Group 2A. However, the only source of radium compounds in nature is in uranium minerals. Why?

Of the 114 -elements known, only two are liquids at room temperature \(\left(25^{\circ} \mathrm{C}\right)\). What are they? (Hint: One element is a familiar metal and the other element is in Group 7A.)

(a) Which elements are most likely to form ionic compounds? (b) Which metallic elements are most likely to form cations with different charges?

The Group \(1 \mathrm{~B}\) metals, \(\mathrm{Cu}, \mathrm{Ag},\) and \(\mathrm{Au},\) are called coinage metals. What chemical properties make them specially suitable for making coins and jewels?
See all solutions

Recommended explanations on Chemistry Textbooks

Chemistry Branches

Read Explanation

Chemical Analysis

Read Explanation

Ionic and Molecular Compounds

Read Explanation

Organic Chemistry

Read Explanation

Nuclear Chemistry

Read Explanation

The Earths Atmosphere

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free