The diameter of a neutral helium atom is about \(1 \times 10^{2} \mathrm{pm}\). Suppose that we could line up helium atoms side by side in contact with one another. Approximately how many atoms would it take to make the distance from end to end \(1 \mathrm{~cm} ?\)

Short Answer

Expert verified
Approximately \(10^{12}\) helium atoms would be needed to make up a distance of 1 cm when placed side by side in contact with each other.

Step by step solution

01

Convert the distance to same unit

The diameter of the helium atom is given in picometers (pm) while the desired total distance is given in centimeters (cm). To compare the two and establish how many atoms fit into the given distance, they need to be in the same units. Consider that \(1 \mathrm{m} = 10^{12} \mathrm{~pm}\) and \(1 \mathrm{m} = 10^{2} \mathrm{~cm}\), then convert 1 cm to picometers: \(1 \mathrm{~cm} = 1 \mathrm{~cm} \times \frac{10^{2} \mathrm{~m}}{1 \mathrm{~cm}} \times \frac{10^{12} \mathrm{~pm}}{1 \mathrm{~m}} = 10^{14} \mathrm{~pm}\)
02

Calculate number of atoms

Now, the total distance and the diameter of one atom are both in picometers. Divide the total distance by the diameter of one atom to find out how many atoms can fit into the distance: Number of atoms = Total distance (in pm) / Diameter of one atom (in pm) = \(10^{14} \mathrm{~pm} / (1 \times 10^{2} \mathrm{~pm}) = 10^{12}\)

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