Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 2: Problem 72

Predict the formula and name of a binary compound formed from these elements: (a) \(\mathrm{Na}\) and \(\mathrm{H},\) (b) \(\mathrm{B}\) and \(\mathrm{O},(\mathrm{c}) \mathrm{Na}\) and \(\mathrm{S},(\mathrm{d}) \mathrm{Al}\) and \(\mathrm{F}\) (e) \(\mathrm{F}\) and \(\mathrm{O},\) (f) \(\mathrm{Sr}\) and \(\mathrm{Cl}\).

Short Answer

Expert verified
(a) Sodium Hydride, \(\mathrm{NaH}\), (b) Boron Trioxide, \(\mathrm{B_2O_3}\), (c) Sodium Sulfide, \(\mathrm{Na_2S}\), (d) Aluminum Fluoride, \(\mathrm{AlF_3}\), (e) Oxygen Difluoride, \(\mathrm{OF_2}\), (f) Strontium Chloride, \(\mathrm{SrCl_2}\)

Step by step solution

01

Understand Valency

The first step is to understand the valency or the charge of each element. Elements in the same group (vertical column) of the periodic table have the same valence or outer shell electrons. This determines how many electrons an atom will gain, lose, or share when forming a compound.
02

Formulate Binary Compounds

The second step is to combine the elements to form a binary compound. The overall compound must be electrically neutral, meaning the sum of the charges should be zero. This means the numbers (or ratio) of each atom in the compound depend on their charges to neutralize each other.
03

Name The Compounds

Finally, name the compounds. The name of a binary compound follows the pattern of 'first element's name + base of second element's name + -ide'. In names of binary compounds, the total valence doesn't have to be specified as it is implied.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Elements whose names end with "-ium" are usually metals; sodium is one example. Identify a nonmetal whose name also ends with "-ium."

Why is magnesium chloride \(\left(\mathrm{MgCl}_{2}\right)\) not called magnesium(II) chloride?

Which of these are elements, which are molecules but not compounds, which are compounds but not molecules, and which are both compounds and molecules? (a) \(\mathrm{SO}_{2},\) (b) \(\mathrm{S}_{8},\) (c) \(\mathrm{Cs},\) (d) \(\mathrm{N}_{2} \mathrm{O}_{5},\) (e) O, (f) \(\mathrm{O}_{2},(\mathrm{~g}) \mathrm{O}_{3},(\mathrm{~h}) \mathrm{CH}_{4},\) (i) \(\mathrm{KBr},(\mathrm{j}) \mathrm{S},(\mathrm{k}) \mathrm{P}_{4},(\mathrm{l}) \mathrm{LiF}\)

Define these terms: (a) atomic number, (b) mass number. Why does a knowledge of atomic number enable us to deduce the number of electrons present in an atom?

Write the molecular formula of glycine, an amino acid present in proteins. The color codes are: black (carbon), blue (nitrogen), red (oxygen), and gray (hydrogen).
See all solutions

Recommended explanations on Chemistry Textbooks

Chemistry Branches

Read Explanation

Kinetics

Read Explanation

Organic Chemistry

Read Explanation

Chemical Reactions

Read Explanation

Inorganic Chemistry

Read Explanation

Ionic and Molecular Compounds

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free