Give the oxidation numbers of the metals in these species: (a) \(\mathrm{K}_{3}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]\) (b) \(\mathrm{K}_{3}\left[\mathrm{Cr}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\right]\) (c) \(\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-}\)

Short Answer

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In these species, the oxidation numbers of the metals are: (a) Iron (Fe) is +3, (b) Chromium (Cr) is +3, and (c) Nickel (Ni) is +2.

Step by step solution

01

Analyze first species

In the first species \(\mathrm{K}_{3}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]\), we know that the oxidation number of potassium (K) is +1 and the oxidation number of cyanide (CN) is -1. For the overall molecule to be neutral, the oxidation number of iron (Fe) has to be +3.
02

Analyze second species

Looking at the second species \(\mathrm{K}_{3}\left[\mathrm{Cr}\left(\mathrm{C}_{2}\mathrm{O}_{4}\right)_{3}\right]\), the oxidation number of potassium (K) is +1 and the oxidation number of oxalate ion \(\mathrm{(C}_{2}\mathrm{O}_{4})\) is -2. Calculating for chromium (Cr), the oxidation number will be +3.
03

Analyze third species

Observe the third species \(\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-}\), in which the oxidation number of cyanide (CN) is -1. The molecule carries 2- charge, hence the sum of oxidation numbers has to equal -2. Therefore, the oxidation number of nickel (Ni) will be +2.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Oxidation State Determination
Understanding the oxidation state, or oxidation number, of an element in a compound is fundamental in chemistry, especially in examining redox reactions and coordination compounds. An oxidation state is a number assigned to an element in a chemical form which represents the number of electrons lost or gained by an atom of that element in the compound.

In the context of coordination compounds, determining the oxidation state can be slightly more complex due to the nature of the bonds between the central metal and the ligands. However, by using simple rules and algebraic calculations, one can deduce the oxidation numbers efficiently.

General Approach for Oxidation State Determination

  • Identify the known oxidation states of ligands and counter ions.
  • Consider the overall charge of the compound.
  • Apply the concept that the sum of the oxidation states in a molecule equals the overall charge.
  • Solve for the unknown oxidation state, usually that of the central metal atom.

Following these steps allows us to figure out that metals like iron (Fe), chromium (Cr), and nickel (Ni), in their respective coordination complexes, have oxidation states of +3, +3, and +2 respectively.
Coordination Chemistry
Coordination chemistry is a branch of inorganic chemistry dealing with the study of coordination compounds. These are complex molecules that consist of a central metal atom or ion bonded to surrounding molecules or ions, known as ligands. Coordination compounds are unique due to their properties and the variety of structures they can form.

Understanding Complex Ions

  • Central Metal Ion/Atom: Typically a transition metal with vacant orbitals ready to accept electron pairs from ligands.
  • Ligands: Molecules or ions that donate pairs of electrons to the metal, forming coordinate covalent bonds. Examples include water, ammonia, cyanide, and oxalate.
  • Coordination Number: Represents the number of ligand electron pairs bonded to the central metal.
  • Charge Considerations: The sum of the central metal's oxidation state and the charges of the ligands must equal the charge of the entire coordination complex.

In our exercise example, potassium acts as a counter ion to the complex ions, balancing the overall charge. Ligands like cyanide and oxalate form specific and identifiable charge patterns that assist in the determination of the central metal's oxidation state.
Redox Chemistry
Redox chemistry, which stands for reduction-oxidation chemistry, involves the transfer of electrons between two species. It's the driving force behind a breadth of chemical processes, from biological systems to industrial applications. In redox reactions, one species undergoes oxidation (loss of electrons) while another undergoes reduction (gain of electrons).

Role of Oxidation States in Redox Reactions

  • Identify Redox Couples: Analyzing the changes in oxidation states helps in identifying the species that get oxidized and reduced.
  • Determine the Direction of Electron Transfer: Electrons move from the species being oxidized to the one being reduced.
  • Balance Equations: Knowing the oxidation states can facilitate the balancing of redox equations through techniques like the half-reaction method.

In coordination chemistry, redox processes can involve the central metal undergoing changes in oxidation state. Ligands can influence these redox processes by stabilizing certain oxidation states of the metal. With our textbook exercise examples, it is essential to understand the oxidation states to analyze any redox behavior within coordination complexes.

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Most popular questions from this chapter

\(\left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2} \mathrm{Cl}_{2}\right]\) is found to exist in two geometric isomers designated I and II, which react with oxalic acid as follows: $$\begin{aligned}\mathrm{I}+\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4} & \longrightarrow\left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2} \mathrm{C}_{2} \mathrm{O}_{4}\right] \\\\\mathrm{II}+\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4} & \longrightarrow\left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2}\left(\mathrm{HC}_{2} \mathrm{O}_{4}\right)_{2}\right]\end{aligned}$$ Comment on the structures of I and II.

A concentrated aqueous copper(II) chloride solution is bright green in color. When diluted with water, the solution becomes light blue. Explain.

Copper is also known to exist in +3 oxidation state, which is believed to be involved in some biological electron transfer reactions. (a) Would you expect this oxidation state of copper to be stable? Explain. (b) Name the compound \(\mathrm{K}_{3} \mathrm{CuF}_{6}\) and predict the geometry of the complex ion and its magnetic properties. (c) Most of the known Cu(III) compounds have square planar geometry. Are these compounds diamagnetic or paramagnetic?

Complete these statements for the complex ion \(\left[\mathrm{Cr}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{2}\left(\mathrm{H}_{2} \mathrm{O}\right)\right]^{2-} .\) (a) The oxidation number of \(\mathrm{Cr}\) is ____ (b) The coordination number of \(\mathrm{Cr}\) is____ (c) ___ is a bidentate ligand.

In a dilute nitric acid solution, \(\mathrm{Fe}^{3+}\) reacts with thiocyanate ion \(\left(\mathrm{SCN}^{-}\right)\) to form a dark-red complex: $$\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}+\mathrm{SCN}^{-} \rightleftharpoons \mathrm{H}_{2} \mathrm{O}+\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{NCS}\right]^{2+}$$ The equilibrium concentration of \(\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{NCS}\right]^{2+}\) may be determined by how darkly colored the solution is (measured by a spectrometer). In one such experiment, \(1.0 \mathrm{~mL}\) of \(0.20 \mathrm{M} \mathrm{Fe}\left(\mathrm{NO}_{3}\right)_{3}\) was mixed with \(1.0 \mathrm{~mL}\) of \(1.0 \times 10^{-3} M \mathrm{KSCN}\) and \(8.0 \mathrm{~mL}\) of dilute \(\mathrm{HNO}_{3}\). The color of the solution quantitatively indicated that the \(\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{NCS}\right]^{2+}\) concentration was \(7.3 \times 10^{-5} M\). Calculate the formation constant for \(\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{NCS}\right]^{2+}\)

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