Write the formulas for each of these ions and compounds: (a) tetrahydroxozincate(II), (b) pentaaquochlorochromium(III) chloride, (c) tetrabromocuprate(II), (d) ethylenediaminetetraacetatoferrate(II).

Short Answer

Expert verified
The formulas for the given ions and compounds are: (a) \(Zn(OH)_2\), (b) [\(Cr(H2O)_5Cl]Cl_2\), (c) \(CuBr_2\), (d) [\(Fe(CH2CH2(NH2)2)C4H3O4]H2\).

Step by step solution

01

Decipher Tetrahydroxozincate(II)

Tetrahydroxozincate(II) is a compound composed of zinc (Zn) with a +2 charge and four hydroxide (OH) with a -1 charge each. To create a neutral molecule, we need one zinc atom and two hydroxide ions. So, the formula is \(Zn(OH)_2\).
02

Decipher Pentaaquochlorochromium(III) Chloride

Pentaaquochlorochromium(III) chloride is a coordination compound. The 'pentaaquo' part suggests five water (H2O) molecules coordinated to the metal which is chromium (Cr) in this case and has a +3 charge. 'Chloro' indicates the presence of a chlorine (Cl) ion within the coordination sphere. The chloride ion is outside the coordination sphere (also carrying a -1 charge). So, the formula is [\(Cr(H2O)_5Cl]Cl_2\).
03

Decipher Tetrabromocuprate(II)

Tetrabromocuprate(II) is a complex ion with copper (Cu) having a +2 charge and four bromine (Br) with a -1 charge each. To ensure neutrality, we need one copper atom and two bromine ions. The formula is \(CuBr_2\).
04

Decipher Ethylenediaminetetraacetatoferrate(II)

Ethylenediaminetetraacetatoferrate(II) denotes a complex ion, where iron (Fe) has a +2 charge. Ethylenediamine (en) and acetate (CH3COO) are both bidentate ligands which bind twice to the central metal atom. There is one ethylenediamine and four acetate ligands. To achieve a neutral molecule, two protons (H+) are required. So the formula is [\(Fe(CH2CH2(NH2)2)C4H3O4]H2\).

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