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Chapter 20: Problem 22

The complex ion \(\left[\mathrm{Ni}(\mathrm{CN})_{2} \mathrm{Br}_{2}\right]^{2-}\) has a square planar geometry. Draw the structures of the geometric isomers of this complex.

Short Answer

Expert verified
There are two geometric isomers of the complex [\(\mathrm{Ni}(\mathrm{CN})_{2}\mathrm{Br}_{2}\)]^{2-}. The \cis isomer has the two cyanide ligands adjacent to each other, while the \trans isomer has the cyanide ligands across from each other.

Step by step solution

01

Understand Geometric Isomers in Square Planar Complexes

Geometric isomerism is a form of stereoisomerism, a phenomenon where molecules have the same molecular formula, but different spatial arrangements. In square planar complexes, ligands can swap places leading to different arrangements of the molecule. Here, two different types of ligands, cyanide (CN) and bromide (Br), are coordinated to a nickel (Ni) center, forming a square on a plane.
02

Draw First Geometric Isomer

In the first arrangement, both cyanide ligands are adjacent to each other (\cis isomer). Start by drawing a square, and place the Ni at the center. Draw bonds from the Ni to the four corners of the square. Place two CN ligands on two adjacent corners, and the Br on the remaining corners.
03

Draw Second Geometric Isomer

In the second arrangement, the cyanide ligands are across from each other (\trans isomer). Again, draw a square with Ni at the center. This time, however, place the CN ligands on opposite corners, and the Br on the remaining corners.

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