Consider the following two ligand exchange reactions: \(\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}+6 \mathrm{NH}_{3} \rightleftharpoons\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}+6 \mathrm{H}_{2} \mathrm{O}\) $$\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}+3 \mathrm{en} \rightleftharpoons\left[\mathrm{Co}(\mathrm{en})_{3}\right]^{3+}+6 \mathrm{H}_{2} \mathrm{O}$$ (a) Which of the reactions should have a larger \(\Delta S^{\circ}\) ? (b) Given that the \(\mathrm{Co}-\mathrm{N}\) bond strength is approximately the same in both complexes, which reaction will have a larger equilibrium constant? Explain your choices.

Short Answer

Expert verified
Based on a qualitative analysis, both reactions appear to have similar ΔS° due to the same number of particles being produced. Similarly, without more specific information, both reactions could have a similar equilibrium constant, given that the Co-N bond strength (a major influence on ΔH°) is approximately the same in both complexes and ΔS° seems roughly equal for both reactions.

Step by step solution

01

Comparing Entropy Change ΔS°

Entropy gauges the disorder or randomness in a system. In general, the side of the reaction with more particles often has higher entropy, as more particles lead to more disorder. In both reactions, there are the same number of reactants and products (2 reactants and 2 products). However, in the first reaction, the product side forms six molecules of water, while in the second, it also forms six molecules of water. Here, both produce the same number of particles, hence we cannot make an exact quantitative assessment based on this information. More in-depth analysis based on the type of ligand may be required to be entirely accurate.
02

Comparing Equilibrium Constant

The equilibrium constant for a reaction is influenced by the standard Gibbs free energy change (ΔG°). ΔG°, in turn, is related to the enthalpy change (ΔH°) and entropy change (ΔS°) by the equation ΔG° = ΔH° - TΔS°. Given that the Co-N bond strength is roughly the same in both complexes, we can infer that the enthalpy change ΔH° is likely to be similar, as bond breaking and making processes are the major contributors to enthalpy change. Entropy change ΔS° appears to be roughly the same for both reactions. Therefore, without more specific details, it could be assumed that both reactions may have a similar equilibrium constant.

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Most popular questions from this chapter

Define the terms (a) labile complex, (b) inert complex.

How many geometric isomers are in these species: (a) \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{2} \mathrm{Cl}_{4}\right]^{-},(\mathrm{b})\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{3} \mathrm{Cl}_{3}\right] ?\)

In a dilute nitric acid solution, \(\mathrm{Fe}^{3+}\) reacts with thiocyanate ion \(\left(\mathrm{SCN}^{-}\right)\) to form a dark-red complex: $$\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}+\mathrm{SCN}^{-} \rightleftharpoons \mathrm{H}_{2} \mathrm{O}+\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{NCS}\right]^{2+}$$ The equilibrium concentration of \(\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{NCS}\right]^{2+}\) may be determined by how darkly colored the solution is (measured by a spectrometer). In one such experiment, \(1.0 \mathrm{~mL}\) of \(0.20 \mathrm{M} \mathrm{Fe}\left(\mathrm{NO}_{3}\right)_{3}\) was mixed with \(1.0 \mathrm{~mL}\) of \(1.0 \times 10^{-3} M \mathrm{KSCN}\) and \(8.0 \mathrm{~mL}\) of dilute \(\mathrm{HNO}_{3}\). The color of the solution quantitatively indicated that the \(\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{NCS}\right]^{2+}\) concentration was \(7.3 \times 10^{-5} M\). Calculate the formation constant for \(\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{NCS}\right]^{2+}\)

The formation constant for the reaction \(\mathrm{Ag}^{+}+\) \(2 \mathrm{NH}_{3} \rightleftharpoons\left[\mathrm{Ag}\left(\mathrm{NH}_{3}\right)_{2}\right]^{+}\) is \(1.5 \times 10^{7}\) and that for the reaction \(\mathrm{Ag}^{+}+2 \mathrm{CN}^{-} \rightleftharpoons\left[\mathrm{Ag}(\mathrm{CN})_{2}\right]^{-}\) is 1.0 \(\times 10^{21}\) at \(25^{\circ} \mathrm{C}\) (see Table 17.4 ). Calculate the equilibrium constant at \(25^{\circ} \mathrm{C}\) for the reaction $$\left[\mathrm{Ag}\left(\mathrm{NH}_{3}\right)_{2}\right]^{+}+2 \mathrm{CN}^{-} \rightleftharpoons\left[\mathrm{Ag}(\mathrm{CN})_{2}\right]^{-}+2 \mathrm{NH}_{3}$$

A concentrated aqueous copper(II) chloride solution is bright green in color. When diluted with water, the solution becomes light blue. Explain.

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