Strontium- 90 is one of the products of the fission of uranium- \(235 .\) This strontium isotope is radioactive, with a half-life of 28.1 yr. Calculate how long (in yr) it will take for \(1.00 \mathrm{~g}\) of the isotope to be reduced to \(0.200 \mathrm{~g}\) by decay.

Short Answer

Expert verified
It will take 65.2 years for 1 gram of Strontium-90 to be reduced to 0.2 grams through decay.

Step by step solution

01

Determine the Number of Half-Lives

First, we need to determine how many half-lives it takes for 1g of the isotope to be reduced to 0.2g. This is done by dividing the final mass by the initial mass. Given that the initial mass is 1g and the final mass is 0.2g, we use the equation \(N = \log(0.2) / \log(0.5)\) to find that \(N = 2.322\), where \(N\) is the number of half-lives.
02

Determine the Total Time

Now we need to convert the number of half-lives to the total time it would take for the decay. This is done by multiplying the number of half-lives by the half-life of the isotope. Given that the half-life of Strontium-90 is 28.1 years, we use the equation \(T = N \cdot T_{\frac{1}{2}}\) to find that \(T = 2.322 \times 28.1 = 65.2\) years, where \(T\) is the total time.

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