Write complete nuclear equations for these processes: (a) tritium, \({ }^{3} \mathrm{H},\) undergoes \(\beta\) decay; \((\mathrm{b}){ }^{242} \mathrm{Pu}\) undergoes \(\alpha\) -particle emission; \((\mathrm{c})^{131} \mathrm{I}\) undergoes \(\beta\) decay; (d) \(^{251} \mathrm{Cf}\) emits an \(\alpha\) particle.

Short Answer

Expert verified
\(\beta\) -decay: \(^3_1\mathrm{H} \rightarrow ^3_2 \mathrm{He} + ^0_{-1} \beta \) and \(^{131}_53 \mathrm{I} \rightarrow ^{131}_54 \mathrm{Xe} + ^0_{-1} \beta \); \(\alpha\)-decay: \(^{242}_94 \mathrm{Pu} \rightarrow ^{238}_92 \mathrm{U} + ^4_2 \alpha \) and \(^{251}_98 \mathrm{Cf} \rightarrow ^{247}_96 \mathrm{Cm} + ^4_2 \alpha \)

Step by step solution

01

Identify the changes in the atomic and mass number for \(\beta\) and \(\alpha\) decay

In \(\beta\) decay, a neutron changes into a proton and an electron (the \(\beta\) particle) which is ejected. Thus, the atomic number increases by 1, while the mass number remains the same. In \(\alpha\) decay, a nucleus emits an \(\alpha\) particle which consists of 2 protons and 2 neutrons. Thus, the atomic number decreases by 2 and the mass number by 4.
02

Write the nuclear equation for tritium (\(^3 \mathrm{H}\)) undergoing \(\beta\) decay

Use the information from step 1, the equation should be: \(^3_1\mathrm{H} \rightarrow ^3_2 \mathrm{He} + ^0_{-1} \beta \)
03

Write the nuclear equation for \(^{242} \mathrm{Pu}\) undergoing \(\alpha\) decay

Use the information from step 1, the equation should be: \(^{242}_94 \mathrm{Pu} \rightarrow ^{238}_92 \mathrm{U} + ^4_2 \alpha \)
04

Write the nuclear equation for \(^{131} \mathrm{I}\) undergoing \(\beta\) decay

Use the information from step 1, the equation should be: \(^{131}_53 \mathrm{I} \rightarrow ^{131}_54 \mathrm{Xe} + ^0_{-1} \beta \)
05

Write the nuclear equation for \(^{251} \mathrm{Cf}\) emitting an \(\alpha\) particle

Use the information from step 1, the equation should be: \(^{251}_98 \mathrm{Cf} \rightarrow ^{247}_96 \mathrm{Cm} + ^4_2 \alpha \)

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