A sample containing \(\mathrm{NaCl}, \mathrm{Na}_{2} \mathrm{SO}_{4},\) and \(\mathrm{NaNO}_{3}\) gives the following elemental analysis: Na: 32.08 percent; O: 36.01 percent; Cl: 19.51 percent. Calculate the mass percent of each compound in the sample.

Given that the Sodium mass percent is 32.08. This represents the total mass percent of Sodium in both Sodium Sulfate and Sodium Chloride. Therefore, the total mass percent of the compounds is 32.08%.

As Sodium Chloride (NaCl) is the only compound that contains Chlorine, the given Chlorine mass percent 19.51% directly corresponds to the mass percent of Sodium Chloride. Hence, the mass percent of Sodium Chloride (NaCl) in the sample is 19.51%.

Given the total Oxygen mass percent is 36.01%. Since we only need to consider Sodium Sulfate (Na2SO4) and Sodium Nitrate (NaNO3) while calculating Oxygen mass percent (as Sodium Chloride doesn’t contain Oxygen), we subtract the Oxygen mass percent contributed by Sodium Nitrate (NaNO3). The Oxygen mass percent in NaNO3 can be calculated as NaNO3 mass percent * Oxygen mass percent in NaNO3 = [100% - (NaCl mass percent + total Sodium salts mass percent)] * (Oxygen mass in NaNO3 / molar mass of NaNO3). The remaining Oxygen mass percent will be the effective Oxygen mass percent in Sodium Sulfate (Na2SO4). To obtain Sodium Sulfate mass percent, divide the obtained Oxygen mass percent by the Oxygen mass percent in Na2SO4 and multiply by the molar mass of Na2SO4.

Finally, subtract the mass percents of Sodium Chloride (NaCl) and Sodium Sulfate (Na2SO4) from 100% to get the mass percent of Sodium Nitrate (NaNO3) in the sample.