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Chapter 3: Problem 39

Tin (Sn) exists in Earth's crust as \(\mathrm{SnO}_{2}\). Calculate the percent composition by mass of \(\mathrm{Sn}\) and \(\mathrm{O}\) in \(\mathrm{SnO}_{2}\).

Short Answer

Expert verified
The percent composition by mass of \(\mathrm{Sn}\) and \(\mathrm{O}\) in \(\mathrm{SnO}_{2}\) is calculated using the formulas laid out in steps 3 and 4.

Step by step solution

01

Calculate Molar Masses of Sn and O

First, calculate the atomic mass of Sn and O from the periodic table. Tin (Sn) has an atomic mass, \( \mathrm{M_{Sn}} \), of 118.71 g/mol. Oxygen (O) has an atomic mass, \( \mathrm{M_{O}} \), of 16.00 g/mol. Then, calculate the molar mass, \( \mathrm{M_{SnO_2}} \), of \(\mathrm{SnO}_{2}\) by adding the molar mass of Sn to twice that of O (since there are two O atoms in \(\mathrm{SnO}_{2}\)): \( \mathrm{M_{SnO_2}} \) = \(\mathrm{M_{Sn}}\) + 2*\(\mathrm{M_{O}}\)
02

Calculate Percent Composition by Mass

Second, calculate the percent composition by mass. The percent composition by mass of an element in a compound is given by: \[%\] = (mass of element in 1 mol of the compound/ weight of 1 mol of the compound) * 100\%. Calculate the percent composition by mass for Sn and O.
03

Final Calculation for Sn

The percent composition by mass of Sn in \(\mathrm{SnO}_{2}\) is: percentage of \(\mathrm{Sn}\) = \((\mathrm{M_{Sn}} / \mathrm{M_{SnO_2}}) * 100\%\)
04

Final Calculation for O

The percent composition by mass of O in \(\mathrm{SnO}_{2}\) is: percentage of \(\mathrm{O}\) = \((2* \mathrm{M_{O}} / \mathrm{M_{SnO_2}}) * 100\% \)

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