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Chapter 3: Problem 51

The anticaking agent added to Morton salt is calcium silicate, \(\mathrm{CaSiO}_{3}\). This compound can absorb up to 2.5 times its mass of water and still remains a freeflowing powder. Calculate the percent composition of \(\mathrm{CaSiO}_{3}\)

Short Answer

Expert verified
The percent composition of \(CaSiO_3\) is roughly 40.05% \(Ca\), 28.06% \(Si\), and 31.89% \(O\).

Step by step solution

01

Calculate Molar Mass of \(\mathrm{CaSiO}_3\)

First, find the molar mass of each element in the compound and multiply it by the number of atoms of that element in the formula. According to the periodic table, the molar masses are \(\mathrm{Ca} = 40.08 \, \mathrm{g/mol}\), \(\mathrm{Si} = 28.09 \, \mathrm{g/mol}\), and \(\mathrm{O} = 16.00 \, \mathrm{g/mol}\). The molar mass of \(\mathrm{CaSiO}_3\) is \(40.08 \, \mathrm{g/mol} + 28.09 \, \mathrm{g/mol} + 3(16.00 \, \mathrm{g/mol}) = 100.09 \, \mathrm{g/mol}\).
02

Calculate Percent Composition

The percent composition for each element in a compound is calculated as the molar mass of the element divided by the molar mass of the compound, multiplied by 100. For \(\mathrm{Ca}\), \(percentCa = (40.08 / 100.09) * 100 = 40.05 \%\). For \(\mathrm{Si}\), \(percentSi = (28.09 / 100.09) * 100 = 28.06 \%\). For \(\mathrm{O}\), because there are three oxygen atoms, \(percentO = (3 * 16.00 / 100.09) * 100 = 31.89 \%\).
03

Verify Solution

To verify the solution, sum all the percentage compositions. If they add up to approximately 100.0%, the calculations have been done correctly. \(40.05 \% + 28.06 \% + 31.89 \% = 100.0 \%\).

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Most popular questions from this chapter

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