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Chapter 4: Problem 15

What is the difference between an ionic equation and a molecular equation?

Short Answer

Expert verified
An ionic equation represents compounds as dissociated ions, showing all the particles as they realistically exist in the solution. A molecular equation, on the other hand, shows the reaction occurring between the neutral compounds as a whole and not as separated ions.

Step by step solution

01

Understanding Molecular Equation

A molecular equation is a balanced chemical equation where the ionic compounds are expressed as molecules instead of component ions.
02

Understanding Ionic Equation

An ionic equation is a chemical equation where the electrolytes in aqueous solution are written as dissociated ions.
03

Key Differences

The key difference between these two lies in the fact that the ionic equation shows all the particles involved in the reaction as they realistically exist in the solution, while the molecular equation shows the neutral compounds as whole rather than as separated ions.

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Most popular questions from this chapter

A \(3.664-\mathrm{g}\) sample of a monoprotic acid was dissolved in water and required \(20.27 \mathrm{~mL}\) of a \(0.1578 \mathrm{M}\) \(\mathrm{NaOH}\) solution for neutralization. Calculate the molar mass of the acid.

Water is added to \(25.0 \mathrm{~mL}\) of a \(0.866 \mathrm{M} \mathrm{KNO}_{3}\) solution until the volume of the solution is exactly \(500 \mathrm{~mL}\). What is the concentration of the final solution?

Give Arrhenius's and Bronsted's definitions of an acid and a base. Why are Bronsted's definitions more useful in describing acid-base properties?

What are the characteristics of an acid-base neutralization reaction?

A \(1.00-\mathrm{g}\) sample of a metal \(\mathrm{X}\) (that is known to form \(\mathrm{X}^{2+}\) ions) was added to a \(0.100 \mathrm{~L}\) of \(0.500 \mathrm{M}\) \(\mathrm{H}_{2} \mathrm{SO}_{4}\). After all the metal had reacted, the remaining acid required \(0.0334 \mathrm{~L}\) of \(0.500 \mathrm{M} \mathrm{NaOH}\) solution for neutralization. Calculate the molar mass of the metal and identify the element.
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