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Chapter 4: Problem 16

What is the advantage of writing net ionic equations?

Short Answer

Expert verified
Net ionic equations simplify chemical reactions by excluding spectator ions and focusing specifically on the substances and ions that change during the reaction. They help to clearly depict what is happening, especially in aqueous solutions, and to differentiate reactions that result in precipitation, ionization, or formation/dissociation of covalent compounds.

Step by step solution

01

Define the concept

A net ionic equation represents the ions and compounds that change in a chemical reaction, excluding the 'spectator ions', which are ions that do not participate in the reaction.
02

Discuss core advantage

The main advantage of writing net ionic equations is that they simplify the process of writing chemical equations by focusing solely on the substances and ions that actually change during the reaction. They provide a clear picture of what is really occurring in aqueous solutions.
03

Highlight application

Another advantage is that net ionic equations are applicable to reactions that lead to the formation of precipitates, the ionization of weak acids or bases, or the formation or dissociation of covalent compounds, whereas traditional molecular equations do not clearly differentiate these cases.

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Most popular questions from this chapter

Balance the following equations and write the corresponding ionic and net ionic equations (if appropriate): (a) \(\operatorname{HBr}(a q)+\mathrm{NH}_{3}(a q) \longrightarrow\) (b) \(\mathrm{Ba}(\mathrm{OH})_{2}(a q)+\mathrm{H}_{3} \mathrm{PO}_{4}(a q) \longrightarrow\) (c) \(\mathrm{HClO}_{4}(a q)+\mathrm{Mg}(\mathrm{OH})_{2}(s) \longrightarrow\)

Calculate the molarity of each of the following solutions: (a) \(29.0 \mathrm{~g}\) of ethanol \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\right)\) in \(545 \mathrm{~mL}\) of solution, (b) \(15.4 \mathrm{~g}\) of sucrose \(\left(\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}\right)\) in \(74.0 \mathrm{~mL}\) of solution, (c) \(9.00 \mathrm{~g}\) of sodium chloride \((\mathrm{NaCl})\) in \(86.4 \mathrm{~mL}\) of solution.

Based on oxidation number, explain why carbon monoxide (CO) is flammable but carbon dioxide \(\left(\mathrm{CO}_{2}\right)\) is not.

You are given a water-soluble compound X. Describe how you would determine whether it is an electrolyte or a nonelectrolyte. If it is an electrolyte, how would you determine whether it is strong or weak? \(?\)

Calculate the molarity of each of the following solutions: (a) \(6.57 \mathrm{~g}\) of methanol \(\left(\mathrm{CH}_{3} \mathrm{OH}\right)\) in \(1.50 \times\) \(10^{2} \mathrm{~mL}\) of solution, (b) \(10.4 \mathrm{~g}\) of calcium chloride \(\left(\mathrm{CaCl}_{2}\right)\) in \(2.20 \times 10^{2} \mathrm{~mL}\) of solution, (c) \(7.82 \mathrm{~g}\) of naphthalene \(\left(\mathrm{C}_{10} \mathrm{H}_{8}\right)\) in \(85.2 \mathrm{~mL}\) of benzene solution.
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