Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 4: Problem 40

For the complete redox reactions given here, write the half-reactions and identify the oxidizing and reducing agents: (a) \(4 \mathrm{Fe}+3 \mathrm{O}_{2} \longrightarrow 2 \mathrm{Fe}_{2} \mathrm{O}_{3}\) (b) \(\mathrm{Cl}_{2}+2 \mathrm{NaBr} \longrightarrow 2 \mathrm{NaCl}+\mathrm{Br}_{2}\) (c) \(\mathrm{Si}+2 \mathrm{~F}_{2} \longrightarrow \mathrm{SiF}_{4}\) (d) \(\mathrm{H}_{2}+\mathrm{Cl}_{2} \longrightarrow 2 \mathrm{HCl}\)

Short Answer

Expert verified
(a) Oxidizing agent: O2, Reducing agent: Fe \n (b) Oxidizing agent: Cl2, Reducing agent: Br- \n (c) Oxidizing agent: F2, Reducing agent: Si \n (d) Oxidizing agent: Cl2, Reducing agent: H2

Step by step solution

01

Identify oxidation and reduction

A substance is being oxidized if it loses electrons and being reduced if it gains electrons. In (a), Fe loses electrons and changes to Fe2+ (thus being oxidized), while O2 gains electrons and changes to O2- (thus being reduced). In (b), Cl2 gains electrons and changes to Cl- (thus being reduced), while Br- loses electrons and changes to Br2 (thus being oxidized). Similar process for (c) and (d).
02

Write half-reactions

(a) Oxidation: \(4Fe \rightarrow 4Fe^{2+} + 8e^{-}\), Reduction: \(3O_{2} + 12e^{-} \rightarrow 6O^{2-}\) \n (b) Oxidation: \(2Br^{-} \rightarrow Br2 + 2e^{-}\), Reduction: \(Cl2 + 2e^{-} \rightarrow 2Cl^{-}\) \n (c) Oxidation: \(\mathrm{Si} \rightarrow \mathrm{Si^{4+}} + 4e^{-}\), Reduction: \(\mathrm{2F2} + 8e^{-} \rightarrow 4F^{-}\) \n (d) Oxidation: \(\mathrm{H2} \rightarrow 2H^{+} + 2e^{-}\), Reduction: \(\mathrm{Cl2} + 2e^{-} \rightarrow 2Cl^{-}\)
03

Identify oxidizing and reducing agents

The oxidizing agent is the substance that is reduced, while the reducing agent is the substance that is oxidized. (a) Oxidizing agent: O2, Reducing agent: Fe \n (b) Oxidizing agent: Cl2, Reducing agent: Br- \n (c) Oxidizing agent: F2, Reducing agent: Si \n (d) Oxidizing agent: Cl2, Reducing agent: H2

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Write the equation that enables us to calculate the concentration of a diluted solution. Give units for all the terms.

Acetic acid \(\left(\mathrm{CH}_{3} \mathrm{COOH}\right)\) is an important ingredient of vinegar. A sample of \(50.0 \mathrm{~mL}\) of a commercial vinegar is titrated against a \(1.00 \mathrm{M} \mathrm{NaOH}\) solution. What is the concentration (in \(M\) ) of acetic acid present in the vinegar if \(5.75 \mathrm{~mL}\) of the base were required for the titration?

What is an oxidation number? How is it used to identify redox reactions? Explain why, except for ionic compounds, oxidation number does not have any physical significance.

How does an acid-base indicator work?

A \(3.664-\mathrm{g}\) sample of a monoprotic acid was dissolved in water and required \(20.27 \mathrm{~mL}\) of a \(0.1578 \mathrm{M}\) \(\mathrm{NaOH}\) solution for neutralization. Calculate the molar mass of the acid.
See all solutions

Recommended explanations on Chemistry Textbooks

The Earths Atmosphere

Read Explanation

Kinetics

Read Explanation

Chemical Analysis

Read Explanation

Physical Chemistry

Read Explanation

Nuclear Chemistry

Read Explanation

Chemical Reactions

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free