Give the oxidation number for the following species: \(\mathrm{H}_{2}, \mathrm{Se}_{8}, \mathrm{P}_{4}, \mathrm{O}, \mathrm{U}, \mathrm{As}_{4}, \mathrm{~B}_{12}\)

Short Answer

Expert verified
The oxidation numbers for the given species are: \(H_{2} = 0\), \(Se_{8} = 0\), \(P_{4} = 0\), \(O = 0\), \(U = 0\), \(As_{4} = 0\), \(B_{12} = 0\)

Step by step solution

01

Understand the concept of Oxidation Number

Oxidation number is the charge an atom would have if electrons in each bond were given to the more electronegative atom. For a molecule, sum of oxidation numbers of all the atoms is zero. For elements in their molecular form, the atoms are identical and there is no electronegativity difference so the bond is nonpolar, hence the atoms have oxidation state = 0.
02

Identify Oxidation Number for \(H_{2}\)

As \(H_{2}\) is an element in its molecular form which is hydrogen, its oxidation state is 0.
03

Identify Oxidation Number for \(Se_{8}\)

In \(Se_{8}\), which is an element in its molecular form (selenium), all selenium atoms have the same electronegativity, hence its oxidation state is 0.
04

Identify Oxidation Number for \(P_{4}\)

For \(P_{4}\), it is an element in its molecular form (phosphorus), its oxidation state is 0.
05

Identify Oxidation Number for \(O\)

The element \(O\) stands for oxygen. In its atomic form, its oxidation state is 0.
06

Identify Oxidation Number for \( U \)

The symbol \(U\) stands for Uranium. Its atomic form gives it an oxidation state of 0.
07

Identify Oxidation Number for \(As_{4}\)

As \(As_{4}\) is an element in its molecular form which is arsenic, its oxidation state is 0.
08

Identify Oxidation Number for \(B_{12}\)

In \(B_{12}\), it is an element in its molecular form (boron), hence its oxidation state is 0.

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