Nitric acid is a strong oxidizing agent. State which of the following species is least likely to be produced when nitric acid reacts with a strong reducing agent such as zinc metal, and explain why: \(\mathrm{N}_{2} \mathrm{O},\) \(\mathrm{NO}, \mathrm{NO}_{2}, \mathrm{~N}_{2} \mathrm{O}_{4}, \mathrm{~N}_{2} \mathrm{O}_{5}, \mathrm{NH}_{4}^{+}\)

Short Answer

Expert verified
The compound \(\mathrm{NH}_{4}^{+}\) is least likely to be produced when nitric acid reacts with a strong reducing agent such as zinc metal.

Step by step solution

01

Understanding Oxidation States

Firstly, clarify what the oxidation state of nitrogen in each of the listed compounds is: in \(\mathrm{N}_{2} \mathrm{O}\) it is +1, in \(\mathrm{NO}, \mathrm{NO}_{2}, \mathrm{~N}_{2} \mathrm{~O}_{4}\) it is +2, +4, and +4 respectively, in \(\mathrm{N}_{2} \mathrm{O}_{5}\) it is +5, and in \(\mathrm{NH}_{4}^{+}\), it is -3.
02

Understanding reactions with reducing agents

Next, recognize that a reducing agent will donate electrons and thus reduce the oxidation state of nitrogen. Since the nitrogen in \(\mathrm{NH}_{4}^{+}\) already has a low oxidation state (-3), it is least likely to be the product.
03

Final Conclusion

Finally, conclude that \(\mathrm{NH}_{4}^{+}\) is least likely to be produced when nitric acid reacts with a strong reducing agent such as zinc metal because its nitrogen atom is already in a reduced state, and a reducing agent would decrease the oxidation state of nitrogen rather than increase it.

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