Which of these aqueous solutions would you expect to be the best conductor of electricity at \(25^{\circ} \mathrm{C} ?\) Explain your answer. (a) \(0.20 \mathrm{M} \mathrm{NaCl}\) (b) \(0.60 \mathrm{M} \mathrm{CH}_{3} \mathrm{COOH}\) (c) \(0.25 M \mathrm{HCl}\) (d) \(0.20 M \mathrm{Mg}\left(\mathrm{NO}_{3}\right)_{2}\)

Short Answer

Expert verified
The solution \(0.20 M \mathrm{Mg}\left(\mathrm{NO}_{3}\right)_{2}\) would be the best conductor of electricity because it produces the highest number of ions in the solution.

Step by step solution

01

Analyze the Solutions

Firstly, check the substances given: (a) \(0.20 \mathrm{M} \mathrm{NaCl}\) is a strong electrolyte and it will completely dissociate into \(\mathrm{Na^{+}}\) and \(\mathrm{Cl^{-}}\) ions, thus producing 2 ions in the solution. (b) \(0.60 \mathrm{M} \mathrm{CH}_{3} \mathrm{COOH}\) is a weak electrolyte, will partially ionize and produce less number of ions than in the (a) solution, although its molarity is higher. (c) \(0.25 M \mathrm{HCl}\) is a strong electrolyte and will completely dissociate into \(\mathrm{H^{+}}\) and \(\mathrm{Cl^{-}}\) ions, thus producing 2 ions in the solution. (d) \(0.20 M \mathrm{Mg}\left(\mathrm{NO}_{3}\right)_{2}\) will dissociate into one \(\mathrm{Mg^{2+}}\) ion and two \(\mathrm{NO_{3}^{-}}\) ions, thus producing 3 ions in solution.
02

Comparing Concentration of Ions

The molar concentration does not change for weak and strong electrolytes but the number of ions in solution does. We can see that solution (a), (c) yields 2 ions per molecule while solution (d) yields 3 ions per molecule. Clearly, solution (d) \(0.20 M \mathrm{Mg}\left(\mathrm{NO}_{3}\right)_{2}\) will contain more ions because it ionizes to produce 3 ions per molecule.
03

Conclusion

Even though solutions (a) and (c) are strong electrolytes, and (b) has a higher molarity but is a weak electrolyte, the solution (d) \(0.20 M \mathrm{Mg}\left(\mathrm{NO}_{3}\right)_{2}\) appears to be the best conductor of electricity, as it produces the highest number of ions in the solution when compared to other given solutions.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free