Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 4: Problem 97

A \(1.00-\mathrm{g}\) sample of a metal \(\mathrm{X}\) (that is known to form \(\mathrm{X}^{2+}\) ions) was added to a \(0.100 \mathrm{~L}\) of \(0.500 \mathrm{M}\) \(\mathrm{H}_{2} \mathrm{SO}_{4}\). After all the metal had reacted, the remaining acid required \(0.0334 \mathrm{~L}\) of \(0.500 \mathrm{M} \mathrm{NaOH}\) solution for neutralization. Calculate the molar mass of the metal and identify the element.

Short Answer

Expert verified
The molar mass of the metal is approximately \(30.031\, g/mol\). And the metal is identified as Magnesium (Mg).

Step by step solution

01

Calculate the amount of NaOH used in the neutralization

The molarity of NaOH is 0.500 M and the volume of NaOH used is 0.0334 L. The moles of NaOH used can be calculated using the equation Moles = Molarity x Volume. Therefore, Moles of NaOH = \(0.500 M \times 0.0334 L = 0.0167\, moles\)
02

Determine the moles of H2SO4 that reacted with the metal

Since NaOH and H2SO4 chemically react in a 1:1 ratio, the moles of H2SO4 neutralized by NaOH is also 0.0167 moles. The initial moles of H2SO4 can be calculated from its molarity and volume, which is \(0.500 M \times 0.100 L = 0.050\, moles\). Therefore, the moles of H2SO4 that reacted with the metal would be \(0.050 moles - 0.0167 moles = 0.0333\, moles\)
03

Calculate the moles of metal X

The reaction between X and H2SO4 would follow the pattern: \(X + H_2SO_4 -> XSO_4 + 2H\) . Therefore there is a 1:1 molar ratio between metal X and H2SO4. This means the moles of metal X that reacted will be the same as the moles of H2SO4 that reacted which is 0.0333 moles.
04

Calculate the molar mass and identify metal X

The molar mass of the metal can be found by using the equation molar mass = mass / moles. The mass of the metal is given as 1.00 g and we have calculated the moles as 0.0333. So, the molar mass = \(1.00 g / 0.0333 \,moles = 30.031\, g/mol\). Based on the periodic table, the metal with a molar mass close to 30.031 g/mol is Magnesium (Mg) which has a molar mass of 24.31 g/mol.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Describe how to prepare \(1.00 \mathrm{~L}\) of \(0.646 \mathrm{M} \mathrm{HCl}\) solution, starting with a \(2.00 \mathrm{M} \mathrm{HCl}\) solution.

How many grams of \(\mathrm{KOH}\) are present in \(35.0 \mathrm{~mL}\) of a \(5.50 \mathrm{M}\) solution?

Acetic acid \(\left(\mathrm{CH}_{3} \mathrm{COOH}\right)\) is an important ingredient of vinegar. A sample of \(50.0 \mathrm{~mL}\) of a commercial vinegar is titrated against a \(1.00 \mathrm{M} \mathrm{NaOH}\) solution. What is the concentration (in \(M\) ) of acetic acid present in the vinegar if \(5.75 \mathrm{~mL}\) of the base were required for the titration?

Calculate the molarity of each of the following solutions: (a) \(6.57 \mathrm{~g}\) of methanol \(\left(\mathrm{CH}_{3} \mathrm{OH}\right)\) in \(1.50 \times\) \(10^{2} \mathrm{~mL}\) of solution, (b) \(10.4 \mathrm{~g}\) of calcium chloride \(\left(\mathrm{CaCl}_{2}\right)\) in \(2.20 \times 10^{2} \mathrm{~mL}\) of solution, (c) \(7.82 \mathrm{~g}\) of naphthalene \(\left(\mathrm{C}_{10} \mathrm{H}_{8}\right)\) in \(85.2 \mathrm{~mL}\) of benzene solution.

Describe the basic steps involved in gravimetric analysis. How does this procedure help us determine the identity of a compound or the purity of a compound if its formula is known?
See all solutions

Recommended explanations on Chemistry Textbooks

Physical Chemistry

Read Explanation

Chemistry Branches

Read Explanation

Making Measurements

Read Explanation

Chemical Reactions

Read Explanation

Organic Chemistry

Read Explanation

Nuclear Chemistry

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free