Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 5: Problem 102

Under the same conditions of temperature and pressure, which of these gases would behave most ideally: \(\mathrm{Ne}, \mathrm{N}_{2},\) or \(\mathrm{CH}_{4} ?\) Explain.

Short Answer

Expert verified
Under the same conditions of temperature and pressure, Neon (Ne) would behave most ideally because it is the smallest and most nonpolar of the three gases.

Step by step solution

01

Understand the gas concept

In order to answer the question, it's important to first understand the concepts related to gases. An ideal gas is a hypothetical gas that perfectly fits all the assumptions of the kinetic-molecular theory. An ideal gas will exhibit more ideal behavior under lower pressure and higher temperature conditions. In reality, no gas is completely 'ideal', but they are close under normal conditions.
02

Evaluate Ne

Neon (Ne) is a noble gas that lacks polarity because it is a single atom with a balanced electron cloud. It is small and nonpolar, making it a likely candidate for ideal behavior. Noble gases are particularly nonreactive due to their full valence electron shells.
03

Evaluate N2

Nitrogen (N2) is a diatomic molecule so it's larger than Ne, but it lacks polarity because the bond between the two nitrogen atoms is nonpolar. Nitrogen's nonpolarity means it exhibits weak attractive forces, but its relatively larger size could cause deviation from ideal behavior.
04

Evaluate CH4

In Methane (CH4), carbon is bonded to four hydrogen atoms. The molecule is larger and more complex than the other two gases. Further, although methane is nonpolar, the hydrogen atoms can produce a minor polarization effect, meaning it has slightly higher attractive forces.
05

Compare and Conclude

Upon comparison, Neon (Ne) is the smallest and most nonpolar of the three gases. It will have the weakest deviations from ideal behavior. Nitrogen (N2) and Methane (CH4) are larger, and methane has slight polarizability. These factors could cause deviations from ideal behavior. Therefore, Neon would behave most ideally under the given conditions.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The atmospheric pressure at the summit of \(\mathrm{Mt}\). McKinley is \(606 \mathrm{mmHg}\) on a certain day. What is the pressure in atm and in \(\mathrm{kPa} ?\)

The ozone molecules present in the stratosphere absorb much of the harmful radiation from the sun. Typically, the temperature and pressure of ozone in the stratosphere are \(250 \mathrm{~K}\) and \(1.0 \times 10^{-3} \mathrm{~atm},\) respectively. How many ozone molecules are present in \(1.0 \mathrm{~L}\) of air under these conditions?

State the following gas laws in words and also in the form of an equation: Boyle's law, Charles's law, Avogadro's law. In each case, indicate the conditions under which the law is applicable, and give the units for each quantity in the equation.

A sample of nitrogen gas kept in a container of volume \(2.3 \mathrm{~L}\) and at a temperature of \(32^{\circ} \mathrm{C}\) exerts a pressure of \(4.7 \mathrm{~atm} .\) Calculate the number of moles of gas present.

In \(2.00 \mathrm{~min}, 29.7 \mathrm{~mL}\) of He effuse through a small hole. Under the same conditions of pressure and temperature, \(10.0 \mathrm{~mL}\) of a mixture of \(\mathrm{CO}\) and \(\mathrm{CO}_{2}\) effuse through the hole in the same amount of time. Calculate the percent composition by volume of the mixture.
See all solutions

Recommended explanations on Chemistry Textbooks

Chemical Reactions

Read Explanation

Organic Chemistry

Read Explanation

The Earths Atmosphere

Read Explanation

Nuclear Chemistry

Read Explanation

Ionic and Molecular Compounds

Read Explanation

Chemistry Branches

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free