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Chapter 5: Problem 26

Molecular chlorine and molecular fluorine combine to form a gaseous product. Under the same conditions of temperature and pressure it is found that one volume of \(\mathrm{Cl}_{2}\) reacts with three volumes of \(\mathrm{F}_{2}\) to yield two volumes of the product. What is the formula of the product?

Short Answer

Expert verified
The formula of the product is \(\mathrm{ClF}_{3}\).

Step by step solution

01

Identify the ratio of reacting volumes

The problem gives the ratio of the volumes of \(\mathrm{Cl}_{2}\), \(\mathrm{F}_{2}\), and the product as 1:3:2 respectively, according to their reaction.
02

Write unbalanced chemical reaction

Next is to write the chemical reaction using the known reactants, which are \(\mathrm{Cl}_{2}\) and \(\mathrm{F}_{2}\), and unknown product X. This forms: \(\mathrm{Cl}_{2} + \mathrm{F}_{2} \rightarrow X\)
03

Balance the chemical equation according to the gas volume ratio

Given the volume ratios are also the stoichiometric coefficients, the unknown product must contain 2 atoms of chlorine and 6 atoms of fluorine. Therefore, the balanced equation and hence the product becomes: \( \mathrm{Cl}_{2} + 3\mathrm{F}_{2} \rightarrow 2\mathrm{ClF}_{3}\)

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