The internal energy of an ideal gas depends only on its temperature. Do a first-law analysis of this process. A sample of an ideal gas is allowed to expand at constant temperature against atmospheric pressure. (a) Does the gas do work on its surroundings? (b) Is there heat exchange between the system and the surroundings? If so, in which direction? (c) What is \(\Delta E\) for the gas for this process?

Short Answer

Expert verified
The gas indeed does work on its surroundings. There is a heat exchange - heat flows from the surroundings into the system. The change in energy, \(\Delta E\), for the gas in this process is zero as it occurs at a constant temperature.

Step by step solution

01

Addressing If the Gas Does Work

As the gas expands, it does indeed do work on its surroundings. This is because the gas molecules push against the external pressure (in this case, the atmospheric pressure) in order to expand.
02

Discussing Heat Exchange

Since the process is taking place at constant temperature, the internal energy of the gas remains constant. The work done by the gas is compensated by absorbing heat from the surroundings. Thus, heat exchange does occur and the direction is from the surroundings to the system (or the gas).
03

Determining Change in Energy

We know that the change in internal energy \(\Delta E\) is given by the First Law of Thermodynamics, \(\Delta E = Q - W\), where Q is the heat transferred to the system and W is the work done by the system. In this case, since temperature is constant, \(\Delta E = 0\), because the internal energy of an ideal gas depends only on its temperature.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Internal Energy of Ideal Gas
The internal energy of an ideal gas is a concept intrinsic to understanding how gases interact with their environment. Simply put, this energy is related to the microscopic kinetic energy of the gas molecules moving randomly within the container. For an ideal gas, this energy is solely dependent on the temperature of the system.

This implies a pivotal principle: if there’s no change in temperature, there’s also no change in internal energy, denoted by \( \Delta E = 0 \). This is crucial because it helps predict how an ideal gas will behave when subjected to different thermodynamic processes. For instance, during an isothermal process (which occurs at a constant temperature), the internal energy remains constant irrespective of the volume changes or work done by the gas.
Isothermal Expansion
Isothermal expansion is a thermodynamic process where a gas changes volume while maintaining a constant temperature throughout. To maintain this constant temperature, the system must engage in heat exchange with its surroundings.

Imagine holding a balloon filled with gas over a flame. As it heats, it expands, but if you were to move the balloon around to keep the temperature steady, you would be demonstrating isothermal expansion. In reality, to achieve this situation, the system must absorb just the right amount of heat to offset the work done by the gas as it expands.

This process perfectly illustrates two critical concepts: the conservation of energy and the intricate balance between work and heat in thermodynamic systems.
Work Done by Gas
When a gas expands, it pushes against the pressure exerted by its surroundings, which can be other gases or a physical barrier like the walls of a container. This exertion of force over a distance is what we call work done by the gas.

In the context of our ideal gas undergoing an isothermal expansion, work done \( (W) \) can be visualized as the product of pressure and the change in volume, represented by the equation \( W = P \Delta V \). Here, \( P \) stands for the external pressure and \( \Delta V \) is the change in volume. Since the gas does work on its surroundings, it naturally needs energy – this is where heat comes in.
Heat Transfer
Heat transfer in thermodynamics refers to the movement of thermal energy between a system and its surroundings. It is a cornerstone for understanding how energy flows and is transformed within a thermodynamic system.

During isothermal expansion, the work done by a gas is directly related to heat transfer \( (Q) \) from the surroundings into the system. This energy influx must be exactly balanced out by the energy expended in doing work for the internal energy to remain constant. To put it another way, the heat absorbed by the gas enables it to do work on its surroundings.

In practical situations, methods of heat transfer include conduction, convection, and radiation. For our scenario, the gas absorbs heat from the surroundings via these mechanisms to maintain its temperature and allow for expansion.

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Most popular questions from this chapter

(a) A snowmaking machine contains a mixture of compressed air and water vapor at about 20 atm. When the mixture is sprayed into the atmosphere it expands so rapidly that, as a good approximation, no heat exchange occurs between the system (air and water) and its surroundings. (In thermodynamics, such a process is called an adiabatic process.) Do a first law of thermodynamics analysis to show how snow is formed under these conditions. (b) If you have ever pumped air into a bicycle tire, you probably noticed a warming effect at the valve stem. The action of the pump compresses the air inside the pump and the tire. The process is rapid enough to be treated as an adiabatic process. Apply the first law of thermodynamics to account for the warming effect. (c) A driver's manual states that the stopping distance quadruples as the speed doubles; that is, if it takes \(30 \mathrm{ft}\) to stop a car traveling at \(25 \mathrm{mph}\) then it would take \(120 \mathrm{ft}\) to stop a car moving at 50 mph. Justify this statement by using the first law of thermodynamics. Assume that when a car is stopped, its kinetic energy \(\left(\frac{1}{2} m u^{2}\right)\) is totally converted to heat.

From a thermochemical point of view, explain why a carbon dioxide fire extinguisher or water should not be used on a magnesium fire.

Portable hot packs are available for skiers and people engaged in other outdoor activities in a cold climate. The air-permeable paper packet contains a mixture of powdered iron, sodium chloride, and other components, all moistened by a little water. The exothermic reaction that produces the heat is a very common one- the rusting of iron: $$ 4 \mathrm{Fe}(s)+3 \mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{Fe}_{2} \mathrm{O}_{3}(s) $$ When the outside plastic envelope is removed, \(\mathrm{O}_{2}\) molecules penetrate the paper, causing the reaction to begin. A typical packet contains \(250 \mathrm{~g}\) of iron to warm your hands or feet for up to \(4 \mathrm{~h}\). How much heat (in \(\mathrm{kJ}\) ) is produced by this reaction? (Hint: See Appendix 2 for \(\Delta H_{\mathrm{f}}^{\circ}\) values.

Determine the amount of heat (in kJ) given off when \(1.26 \times 10^{4} \mathrm{~g}\) of \(\mathrm{NO}_{2}\) are produced according to the equation $$ \begin{aligned} 2 \mathrm{NO}(g)+\mathrm{O}_{2}(g) \longrightarrow & 2 \mathrm{NO}_{2}(g) \\ \Delta H &=-114.6 \mathrm{~kJ} / \mathrm{mol} \end{aligned} $$

A 44.0-g sample of an unknown metal at \(99.0^{\circ} \mathrm{C}\) was placed in a constant-pressure calorimeter containing \(80.0 \mathrm{~g}\) of water at \(24.0^{\circ} \mathrm{C}\). The final temperature of the system was found to be \(28.4^{\circ} \mathrm{C}\). Calculate the specific heat of the metal. (The heat capacity of the calorimeter is \(\left.12.4 \mathrm{~J} /{ }^{\circ} \mathrm{C} .\right)\)

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