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Chapter 7: Problem 92

Use the Aufbau principle to obtain the ground-state electron configuration of technetium.

Short Answer

Expert verified
The ground-state electron configuration of Technetium, using the Aufbau principle, is \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^5\).

Step by step solution

01

Identify the atomic number of Technetium

Technetium is the 43rd element in the periodic table, so it has 43 electrons in its neutral state.
02

Apply the Aufbau principle

Start filling the electrons in the ascending order of energy level. Following the Aufbau principle, the electron configuration of neutral state Technetium would be \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^5\). Here, each power represents the number of electrons in that orbital.

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Most popular questions from this chapter

A photoelectric experiment was performed by separately shining a laser at \(450 \mathrm{nm}\) (blue light) and a laser at \(560 \mathrm{nm}\) (yellow light) on a clean metal surface and measuring the number and kinetic energy of the ejected electrons. Which light would generate more electrons? Which light would eject electrons with greater kinetic energy? Assume that the same amount of energy is delivered to the metal surface by each laser and that the frequencies of the laser lights exceed the threshold frequency.

A particular form of electromagnetic radiation has a frequency of \(8.11 \times 10^{14} \mathrm{~Hz}\). (a) What is its wavelength in nanometers? In meters? (b) To what region of the electromagnetic spectrum would you assign it? (c) What is the energy (in joules) of one quantum of this radiation?

Why is a boundary surface diagram useful in representing an atomic orbital?

An electron in a hydrogen atom is excited from the ground state to the \(n=4\) state. Comment on the correctness of the following statements (true or false). (a) \(n=4\) is the first excited state. (b) It takes more energy to ionize (remove) the electron from \(n=4\) than from the ground state. (c) The electron is farther from the nucleus (on average) in \(n=4\) than from the ground state. (d) The wavelength of light emitted when the electron drops from \(n=4\) to \(n=1\) is longer than that from \(n=4\) to \(n=2\). (e) The wavelength the atom absorbs in going from \(n=1\) to \(n=4\) is the same as that emitted as it goes from \(n=4\) to \(n=1\).

What is the de Broglie wavelength (in \(\mathrm{nm}\) ) associated with a 2.5 -g Ping-Pong ball traveling 35 mph?
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