A metal ion with a net +3 charge has five electrons in the \(3 \mathrm{~d}\) subshell. Identify the metal.

Short Answer

Expert verified
The metal is Nickel.

Step by step solution

01

Identify the Period

First, identify the period in the periodic table where the 3d subshell is filled. This is the fourth period.
02

Consider the Charge

Next, think about what losing three electrons would mean. The metal ion has a 3+ charge, indicating it has lost three electrons. If it now has five electrons in the 3d subshell, it must have had eight before it lost electrons.
03

Identifying the Element

Look for a transition metal in the fourth period with a configuration ending in 3d8. This is Nickel (Ni). Nickel has 28 electrons in its neutral state, of which 10 are in the d-orbitals (specifically, 4 in 3d). When it loses 3 electrons to form a +3 cation, it would indeed have 5 left in the 3d subshell.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Metal Ion Electron Configuration
Understanding metal ion electron configuration is essential in chemistry, especially when dealing with transition metals. Ions are atoms that have gained or lost electrons, and metal ions typically lose electrons, thus carrying a positive charge.

For instance, a metal ion with a +3 charge has given up three electrons. If this ion now has five electrons in its 3d subshell, we must consider what the electron configuration of the neutral atom looked like. In our case, five 3d electrons in the ion implies there were originally eight 3d electrons. Electron configuration thus helps us trace back to the element's identity on the periodic table.
Periodic Table
The periodic table is the roadmap of elements, illustrating their properties based on atomic structure. The elements are arranged in periods (rows) and groups (columns), with transition metals located in the middle of the table.

Each period correlates with the highest principle energy level of an atom's electrons that gets filled. For example, the 3d subshell corresponds to elements in the fourth period. This interconnection between the electronic structure and the periodic table layout enables us to locate elements by their electron configuration.
Transition Metal Characteristics
Transition metals possess distinctive traits that differ from other elements. Here are some key characteristics:
  • They are typically malleable and have high densities and melting points.
  • Their valence electrons are in d-orbitals, which leads to a range of possible oxidation states.
  • They form colored compounds and are good conductors of heat and electricity.
  • Many transition metals are catalytically active, playing a crucial role in industrial processes.

Understanding these properties allows chemists to predict a transition metal's behavior in reactions and its use in practical applications.
Atomic Structure
Atomic structure refers to the arrangement of electrons, protons, and neutrons within an atom. Electrons are found in energy levels or shells around the nucleus and are further organized into subshells (s, p, d, and f).

The specific arrangement of electrons in these subshells is what we call electron configuration. For transition metals, the arrangement of electrons in the d subshell is particularly complex and important in determining the chemical behavior of the atom. In our exercise example, the 3d subshell plays a crucial role in identifying the element Nickel based on its atomic structure.
Oxidation States
The oxidation state of an atom is a measure of the degree of its oxidation or reduction; it is the hypothetical charge an atom would have if all bonds to atoms of different elements were 100% ionic. Transition metals are known for having multiple possible oxidation states because they can lose different numbers of d electrons.

The +3 charge on a metal ion indicates it has lost three of its valence electrons, and the oxidation state helps chemists understand elements' reactivity, stability, and the types of compounds they can form. By determining the oxidation state, we deduce the electron count before ionization, as illustrated in the exercise where Nickel's 3+ state leads to its identification.

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Most popular questions from this chapter

The \(\mathrm{H}^{-}\) ion and the He atom have two \(1 \mathrm{~s}\) electrons each. Which of the two species is larger? Explain.

With reference to the periodic table, name (a) a halogen element in the fourth period, (b) an element \(\operatorname{sim}\) ilar to phosphorus in chemical properties, (c) the most reactive metal in the fifth period, \((\) d) an element that has an atomic number smaller than 20 and is similar to strontium.

Write ground-state electron configurations for these transition metal ions: (a) \(\mathrm{Sc}^{3+}\) (b) \(\mathrm{Ti}^{4+}\) (c) \(\mathrm{V}^{5+}\) (d) \(\mathrm{Cr}^{3+}\) , (e) \(\mathrm{Mn}^{2+},\) (f) \(\mathrm{Fe}^{2+}\) (h) \(\mathrm{Co}^{2+}\) (g) \(\mathrm{Fe}^{3+}\) (i) \(\mathrm{Ni}^{2+}\) (i) \(\mathrm{Cu}^{+}\) (k) \(\mathrm{Cu}^{2+}\) (1) \(\mathrm{Ag}^{+}\) \((\mathrm{m}) \mathrm{Au}^{+}\) (n) \(\mathrm{Au}^{3+},\) (o) \(\mathrm{Pt}^{2+}\)

In the late 1800 s the British physicist Lord Rayleigh accurately determined the atomic masses of a number of elements, but he obtained a puzzling result with nitrogen. One of his methods of preparing nitrogen was by the thermal decomposition of ammonia: \( 2 \mathrm{NH}_{3}(g) \longrightarrow \mathrm{N}_{2}(g)+3 \mathrm{H}_{2}(g) \) Another method was to start with air and remove oxygen, carbon dioxide, and water vapor from it. Invariably, the nitrogen from air was a little denser (by about 0.5 percent) than the nitrogen from ammonia. Later the English chemist Sir William Ramsay carried out an experiment in which he passed nitrogen, which he had obtained from air by Raleigh's procedure, over red-hot magnesium to convert it to magnesium nitride: \(3 \mathrm{Mg}(s)+\mathrm{N}_{2}(g) \longrightarrow \mathrm{Mg}_{3} \mathrm{~N}_{2}(s)= \)= After all of the nitrogen had reacted with magnesium, Ramsay was left with an unknown gas that would not combine with anything. The atomic mass of this gas was determined to be 39.95 amu. Ramsay called the gas argon, which means "the lazy one" in Greek. (a) Later Rayleigh and Ramsay, with the help of Sir William Crookes, the inventor of the discharge tube, showed that argon was a new element. Describe the type of experiment performed that led them to the conclusion. (b) Why did it take so long to discover argon? (c) Once argon had been discovered, why did it take relatively little time to discover the rest of the noble gases? (d) Why was helium the last noble gas to be discovered on Earth? (e) The only confirmed compound of radon is radon fluoride, \(\mathrm{RnF}\). Give two reasons why there are so few known radon compounds.

Use the second period of the periodic table as an example to show that the sizes of atoms decrease as we move from left to right. Explain the trend.

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