Arrange the following atoms in order of decreasing atomic radius: \(\mathrm{Na}, \mathrm{Al}, \mathrm{P}, \mathrm{Cl}, \mathrm{Mg}\).

Short Answer

Expert verified
The atoms in order of decreasing atomic radius are Na, Mg, Al, P, Cl.

Step by step solution

01

Identify location of elements on the periodic table

First, locate each atom on the periodic table. Sodium (Na) and Magnesium (Mg) are in the third period while Aluminum (Al), Phosphorous (P), and Chlorine (Cl) are in the fourth period.
02

Apply periodic trends to arrange atoms

Next, apply the periodic trends to these elements. On moving from left to right across a period, atomic size decreases. Therefore, among Na, Mg, and Al, Na has the largest atomic radius, followed by Mg and Al. Similarly, in the 2nd group (Na and Mg), atomic radius increases down the group, so Na has a larger atomic radius than Mg.
03

Finalize order of atomic radii

Finally, put together the atomic radii in decreasing order. Starting from the atom with the largest atomic radius to the smallest, the order is: Na, Mg, Al, P, Cl

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