Explain which of these anions is larger, and why: \(\mathrm{Se}^{2-}\) or \(\mathrm{Te}^{2-}\)

Short Answer

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The \( \mathrm{Te}^{2-} \) anion is larger. This is due to the fact that atomic size increases as we move down the periodic table. Tellurium (Te) is located below Selenium (Se) on the table, meaning it has more electron energy levels and therefore, a larger atomic size.

Step by step solution

01

Understanding the Periodic Table

The first thing to remember is that in the Periodic Table, as we move down a group (vertical column), the atomic size or atomic radius increases. This is because each period represents a new energy level in the electron cloud around the nucleus. As such, \( \mathrm{Se}^{2-} \) and \( \mathrm{Te}^{2-} \) are in the same group, with selenium (Se) above tellurium (Te).
02

Analyzing the Atomic Number

Tellurium (Te) has a greater atomic number than Selenium (Se), indicating that there are more protons in the nucleus of Tellurium and also more electrons in its electron cloud. This increased number of energy levels in the electron cloud means that the distance from the nucleus to the outermost energy level of Te will be greater than that of Se.
03

Comparing the size of anions

Considering the above points, we can see that \( \mathrm{Te}^{2-} \) will be larger than \( \mathrm{Se}^{2-} \). Because as we add more energy levels (each additional period on the table), the atomic size increases.

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