Arrange the elements in each of these groups in order of increasing electron affinity: (a) \(\mathrm{Li}, \mathrm{Na}, \mathrm{K}\) (b) \(\mathrm{F}, \mathrm{Cl}, \mathrm{Br}, \mathrm{I}\)

Short Answer

Expert verified
The elements in group (a) arranged in order of increasing electron affinity are \( \mathrm{K} < \mathrm{Na} < \mathrm{Li} \). The elements in group (b) arranged in order of increasing electron affinity are \( \mathrm{I} < \mathrm{Br} < \mathrm{Cl} < \mathrm{F} \).

Step by step solution

01

Identify Trends in Electron Affinity

It should be known that electron affinity increases across a period from left to right and decreases down a group on the periodic table. This is due to the increase in nuclear charge, decrease in atomic radius, and increase in effective nuclear charge across a period.
02

Arrange Group (a) Elements

The elements in group (a) are \( \mathrm{Li}, \mathrm{Na}, \mathrm{K} \). They are located in the same group in the periodic table hence, we would follow the trend rule that electron affinity decreases down a group. So, the order of increasing electron affinity will be \( \mathrm{K} < \mathrm{Na} < \mathrm{Li} \).
03

Arrange Group (b) Elements

The elements in group (b) are \( \mathrm{F}, \mathrm{Cl}, \mathrm{Br}, \mathrm{I} \). They are also located in the same group in the periodic table, so the trend that electron affinity decreases down a group is also applicable here. Thus, the order of increasing electron affinity will be \( \mathrm{I} < \mathrm{Br} < \mathrm{Cl} < \mathrm{F} \).

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