Chapter 8: Problem 70
Predict (and give balanced equations for) the reactions between each of these oxides and water: (a) \(\mathrm{Li}_{2} \mathrm{O},\) (b) \(\mathrm{CaO}\) (c) \(\mathrm{CO}_{2}\).
Short Answer
Expert verified
The balanced equations for the reactions are: \(\mathrm{Li}_{2} \mathrm{O} + \mathrm{H}_2 \mathrm{O} \rightarrow 2\mathrm{LiOH}\), \(\mathrm{CaO} + \mathrm{H}_2 \mathrm{O} \rightarrow \mathrm{Ca(OH)}_{2}\), and \(\mathrm{CO}_{2} + \mathrm{H}_2 \mathrm{O} \rightarrow \mathrm{H}_2\mathrm{CO}_{3}\)
Step by step solution
01
Analyze the first compound
First, consider the reaction of \(\mathrm{Li}_{2} \mathrm{O}\) (Lithium Oxide) with water. Lithium oxide is a basic oxide; when it encounters water, it turns into the corresponding alkali hydroxide. Hence, the equation should look like this: \(\mathrm{Li}_{2} \mathrm{O} + \mathrm{H}_2 \mathrm{O} \rightarrow ?\)
02
Balance the first equation
The products on the right side of the equation will be the corresponding alkali hydroxide, Lithium Hydroxide. The balanced equation would then appear as: \(\mathrm{Li}_{2} \mathrm{O} + \mathrm{H}_2 \mathrm{O} \rightarrow 2 \mathrm{LiOH}\)
03
Analyze the second compound
Next, considering the reaction of \(\mathrm{CaO}\) (Calcium Oxide) with water. Like lithium oxide, calcium oxide too is a basic oxide and forms the corresponding alkali hydroxide upon reacting with water. Therefore, the equation would be: \(\mathrm{CaO} + \mathrm{H}_2 \mathrm{O} \rightarrow ?\)
04
Balance the second equation
The product on the right side of the equation will be the corresponding alkali hydroxide, Calcium Hydroxide. The balanced equation hence becomes: \(\mathrm{CaO} + \mathrm{H}_2 \mathrm{O} \rightarrow \mathrm{Ca(OH)}_{2}\)
05
Analyze the third compound
Lastly, is the reaction of \(\mathrm{CO}_{2}\) (Carbon Dioxide) with water. Carbon dioxide is an acidic oxide and when it reacts with water, it forms a weak acid, in this case, carbonic acid. Therefore, the equation would be: \(\mathrm{CO}_{2} + \mathrm{H}_2 \mathrm{O} \rightarrow ?\)
06
Balance the third equation
The product on the right side of the equation will be the carbonic acid. The balanced equation hence becomes: \(\mathrm{CO}_{2} + \mathrm{H}_2 \mathrm{O} \rightarrow \mathrm{H}_2\mathrm{CO}_{3}\)
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chemical Equation Balancing
Balancing chemical equations is a fundamental skill required to understand the quantitative relationships in a chemical reaction. Here's how to think about it:
Every chemical equation represents a recipe for a chemical reaction. The reactants (ingredients) on the left side must result in products (the finished dish) on the right. However, according to the Law of Conservation of Mass, matter cannot be created or destroyed; thus, you must have the same number of each type of atom on both sides of the equation.
When balancing equations, consider the following steps:
Every chemical equation represents a recipe for a chemical reaction. The reactants (ingredients) on the left side must result in products (the finished dish) on the right. However, according to the Law of Conservation of Mass, matter cannot be created or destroyed; thus, you must have the same number of each type of atom on both sides of the equation.
When balancing equations, consider the following steps:
- Write down the unbalanced equation.
- List the number of each type of atom present in the unbalanced equation.
- Adjust coefficients (the numbers in front of the compounds) to balance the atoms. Begin with one element and move systematically through the equation.
- Ensure that the coefficients are the smallest possible whole numbers that balance the atoms.
- Double-check your work to confirm that the mass is balanced on both sides.
Basic Oxides and Hydroxides
Basic oxides, also known as alkaline oxides, are oxides that react with water to form hydroxides. These oxides are typically formed from the metals in the first two groups of the periodic table (s-block elements), such as lithium and calcium in our examples.
When a basic oxide reacts with water, the reaction produces a hydroxide, which is an ionic compound consisting of metal cations and hydroxide anions (\(\mathrm{OH}^{-}\)). Here are some vital points to understand about the reaction of basic oxides with water:
When a basic oxide reacts with water, the reaction produces a hydroxide, which is an ionic compound consisting of metal cations and hydroxide anions (\(\mathrm{OH}^{-}\)). Here are some vital points to understand about the reaction of basic oxides with water:
- They usually dissolve in water and increase the pH, making the solution alkaline.
- The general reaction can be written as \(\mathrm{Metal Oxide} + \mathrm{H}_2\mathrm{O} \rightarrow \mathrm{Metal} \mathrm{Hydroxide}\).
- The reactivity of the metal determines how violently or gently the reaction proceeds.
Acidic Oxides and Weak Acids
Acidic oxides are oxides that react with water to form an acidic solution. These oxides are typically nonmetals or metals in high oxidation states. One prevalent example is \(\mathrm{CO}_{2}\) (carbon dioxide), which reacts with water to form \(\mathrm{H}_2\mathrm{CO}_{3}\) (carbonic acid), as outlined in the exercise.
When acidic oxides dissolve in water, they can partially ionize to form weak acids or completely ionize to form strong acids, resulting in a decrease in pH. The key features of this reaction are as follows:
When acidic oxides dissolve in water, they can partially ionize to form weak acids or completely ionize to form strong acids, resulting in a decrease in pH. The key features of this reaction are as follows:
- Acidic oxides are also known as acid anhydrides because they can be considered dehydrated forms of acids.
- Their general reaction with water can be written as \(\mathrm{Nonmetal Oxide} + \mathrm{H}_2\mathrm{O} \rightarrow \mathrm{Weak} \mathrm{Acid}\).
- The resulting acids have a higher hydrogen ion concentration in the solution, rendering the solution acidic.