Specify which compound in the following pairs of ionic compounds has the higher lattice energy: (a) \(\mathrm{KCl}\) or \(\mathrm{MgO},\) (b) \(\mathrm{LiF}\) or \(\mathrm{LiBr}\) (c) \(\mathrm{Mg}_{3} \mathrm{~N}_{2}\) or \(\mathrm{NaCl}\). Explain your choice.

Short Answer

Expert verified
(a) MgO has the higher lattice energy. (b) LiF has the higher lattice energy. (c) Mg3N2 has the higher lattice energy.

Step by step solution

01

Identify Charges and Sizes of Ions

Identify the charges and sizes of the ions in the compounds. K+ and Cl- in KCl, Mg2+ and O2- in MgO, Li+ and F- in LiF, Li+ and Br- in LiBr, Mg2+ and N3- in Mg3N2, Na+ and Cl- in NaCl.
02

Compare the Lattice Energy

Compare the lattice energy using the Lattice Energy Law: Higher the charges of the ions and smaller the sizes of ions, higher the lattice energy. Thus, (a) MgO has a higher lattice energy than KCl because Mg2+ and O2- result in a higher lattice energy than K+ and Cl-. (b) LiF has a higher lattice energy than LiBr because F- being smaller in size than Br-, it forms a more energetically stable ionic compound. (c) Mg3N2 has a higher lattice energy than NaCl because Mg2+ and N3- result in a higher lattice energy than Na+ and Cl-.

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